如何使用alamofire httpstatusCode

Question

我想要 httpStatusCode 上的不同 responseDecodable

服務器返回

if statusCode == 200
resonseBody
{id: number}

if statusCode 400..<500
resonseBody
{
code: String
timestamp: String
message: String
}

所以現在我的代碼是

 AF.request(url, method: .post, headers: header).responseData { response in
            switch response.result {
            case .success(let data) :
                guard let response = response.response else {return}
                let json = try? JSONSerialization.jsonObject(with: data)
                switch response.statusCode {
                    case 200:
                    if let json = json as? [String: Any] , let message = json["id"] as? Int{print(message)}
                case (400..<500):
                    if let json = json as? [String: Any] , let message = json["message"] as? String{print(message)}
                default:
                    return
                }
            case .failure(let err) :
                print(err)
            }
        }

我試試這個代碼轉換 responseDecodable

struct a: Codable {var id: Int}

struct b: Codable{
    var code: String
    var timestamp: String
    var message: String
}

AF.request(url, method: .post, headers: header).responseDecodable(of: a.self) { response in
            guard let data = response.value else {return}
            print(data)
            }
            .responseDecodable(of: b.self) { response in
            guard let data = response.value else {return}
            print(data)
            }

但是這樣不管 statusCode 都返回 a 和 b

我想要 statusCode == 200 返回 a 或 statusCode 400..<500 返回 b

我應該怎么辦？

Answer 1

AFAIK，Alamofire 沒有“解碼一個對象成功，另一個對象失敗”的實現。 你必須自己做這件事。

如果您真的想要一個用於 2xx 響應的不同對象和另一個用於 4xx 響應的對象，有幾種方法：

1. 使用validate處理 2xx 響應，並在錯誤處理程序中手動解碼 4xx 響應。

    AF.request(url, method: .post, parameters: parameters, headers: header) .validate(statusCode: 200 ..< 300) // only 2xx are auto-decoded for us; handle 4xx responses in `failure` handler .responseDecodable(of: Foo.self) { response in switch response.result { case .failure(let error): guard let statusCode = response.response?.statusCode, 400 ..< 500 ~= statusCode, let data = response.data, let apiError = try? JSONDecoder().decode(ApiErrorResponse.self, from: data) else { print("other error:", error) // didn't parse `ApiErrorResponse` object, so obviously some other error return } print("apiError:", apiError) // this is our parsed API error object case .success(let foo): print("success:", foo) } }

2. 如果需要，您可以編寫自己的ResponseSerializer以不同方式解析 2xx 和 4xx 響應：

    struct ApiErrorResponse: Decodable, Error { let code: String let timestamp: String let message: String } final class ApiResponseSerializer<T: Decodable>: ResponseSerializer { lazy var decoder = JSONDecoder() private lazy var successSerializer = DecodableResponseSerializer<T>(decoder: decoder) private lazy var errorSerializer = DecodableResponseSerializer<ApiErrorResponse>(decoder: decoder) public func serialize(request: URLRequest?, response: HTTPURLResponse?, data: Data?, error: Error?) throws -> T { if let error = error { throw error } guard let response = response else { throw URLError(.badServerResponse) } switch response.statusCode { case 400 ..< 500: let apiErrorObject = try errorSerializer.serialize(request: request, response: response, data: data, error: nil) throw apiErrorObject default: return try successSerializer.serialize(request: request, response: response, data: data, error: nil) } } }

   然后你可以這樣做：

    AF.request(url, method: .post, parameters: parameters, headers: header) .response(responseSerializer: ApiResponseSerializer<Foo>()) { response in switch response.result { case .failure(.responseSerializationFailed(reason: .customSerializationFailed(error: let apiErrorObject))): print("api response error:", apiErrorObject) case .failure(let error): print("some other error:", error) case .success(let foo): print("success:", foo) } }

   我發現解析錯誤對象的嵌套有點乏味，但它確實從response / responseDecoder完成處理程序中抽象出 2xx 與 4xx 邏輯。

在這兩種情況下，我都認為所有 2xx 響應都是成功的，而不僅僅是 200。一些服務器返回 2xx 代碼，而不僅僅是 200。