創建一個以 FY 作為“鍵”和 Quarter 作為“值”的對象 - JavaScript

Question

我正在嘗試創建一個對象，其“鍵”將是財政年度（FY），“值”是季度日期。

//Format
{
   FY:{
        [Quarter dates]
   },
}

季度日期計數從 1 到 4 不等。如果只給出四分之一的信息，則以上一個 FY 為參考，並增加 1 以了解當前 FY。

根據期間結束日期，我可以對季度進行分組，但計算財政年度是我需要幫助的。 FY 將遵循這些規則。

1. 重復次數最多的季度將是財政年度。

2. 如果季度有兩個不同的年份，每個年份計數為 2，那么我們可以選擇最小的年份作為 FY。 例如：期間 =[06/21]，季度 =[09/20,12/20,03/21,06/21] 然后 FY =2020

公司可以更改其期間結束日期，因此您可以預期季度日期之間存在差距。 在以下示例中，公司使用 12 月作為截至 2019 年的期末，之后他們使用 3 月作為期末。 省略了四分之一（1 月、2 月、3 月）的差距。

const quarters = [
    "12 / 30 / 2021",
    "09 / 30 / 2021",
    "06 / 30 / 2021",
    "03 / 30 / 2021",
    "12 / 30 / 2020",
    "09 / 30 / 2020",
    "06 / 30 / 2020",
    "12 / 30 / 2019",
    "09 / 30 / 2019",
    "06 / 30 / 2019",
    "03 / 30 / 2019",
    "12 / 30 / 2018",
    "09 / 30 / 2018",
    "06 / 30 / 2018",
    "03 / 30 / 2018",
];
const periods = [
    "03 / 30 / 2021",
    "12 / 30 / 2019",
    "12 / 30 / 2018",
    "12/30/2017"
];

const groupQuarters = [];
let group = [];
while (periods.length > 0) {
    let p = new Date(periods[0].toString());
    group = [];
    while (quarters.length > 0) {
        let q = new Date(quarters[0].toString());
        if (q > p) {
            group.push(quarters[0]);
            quarters.shift();
        } else {
            break;
        }
    }
    const yearCal = (groups) => {
        // unable to figure this out.
        return 2020;
    }
    groupQuarters.push({ [yearCal(group)]: group });
    periods.shift();
}


console.log(groupQuarters);

Expected output:
[
  {
      2021: [
          '12 / 30 / 2021',
          '09 / 30 / 2021',
          '06 / 30 / 2021'
      ]
  },
  {
      2020: [
          '03 / 30 / 2021',
          '12 / 30 / 2020',
          '09 / 30 / 2020',
          '06 / 30 / 2020'
      ]
  },
  {
      2019: [
          '12 / 30 / 2019',
          '09 / 30 / 2019',
          '06 / 30 / 2019',
          '03 / 30 / 2019'
      ]
  },
  {
      2018: [
          '12 / 30 / 2018',
          '09 / 30 / 2018',
          '06 / 30 / 2018',
          '03 / 30 / 2018'
      ]
  }
]

Test Case - 2:
const quarters = [
  "12 / 30 / 2020",
  "09 / 30 / 2020",
  "06 / 30 / 2020",
  "03 / 30 / 2020",
  "12 / 30 / 2019",
  "09 / 30 / 2019",
  "06 / 30 / 2019",
  "03 / 30 / 2019",
  "12 / 30 / 2018"
];
const periods = [
  "09 / 30 / 2020",
  "09 / 30 / 2019",
  "09 / 30 / 2018",
];

Expected Output:
[
  {
    2021: [
      '12 / 30 / 2020',
    ]
  },
  {
    2020: [
      "09 / 30 / 2020",
      "06 / 30 / 2020",
      "03 / 30 / 2020",
      "12 / 30 / 2019",
    ]
  },
  {
    2019: [
      "09 / 30 / 2019",
      "06 / 30 / 2019",
      "03 / 30 / 2019",
      "12 / 30 / 2018",
    ]
  },
]

Answer 1

你可以試試 ：

 const quarters = [ "12 / 30 / 2021", "09 / 30 / 2021", "06 / 30 / 2021", "03 / 30 / 2021", "12 / 30 / 2020", "09 / 30 / 2020", "06 / 30 / 2020", "12 / 30 / 2019", "09 / 30 / 2019", "06 / 30 / 2019", "03 / 30 / 2019", "12 / 30 / 2018", "09 / 30 / 2018", "06 / 30 / 2018", "03 / 30 / 2018", ] const periods = [ "03 / 30 / 2021", "12 / 30 / 2019", "12 / 30 / 2018", "12/30/2017" ] const quarters1 = [ "12 / 30 / 2020", "09 / 30 / 2020", "06 / 30 / 2020", "03 / 30 / 2020", "12 / 30 / 2019", "09 / 30 / 2019", "06 / 30 / 2019", "03 / 30 / 2019", "12 / 30 / 2018" ]; const periods1 = [ "09 / 30 / 2020", "09 / 30 / 2019", "09 / 30 / 2018", ]; const getGroupQuarter = (qt, pr) => { let tmpCheck = qt return pr.reduce((result,period) => { let datePeriod = new Date(period) let key = getKeyQuarter(datePeriod) let qtrFill = tmpCheck.filter(quarter => new Date(quarter) > datePeriod) tmpCheck = tmpCheck.filter(quarter =>!(new Date(quarter) > datePeriod)) return !qtrFill.length ? result :[...result, {[key] : qtrFill}] }, []) } const getKeyQuarter = (pr) => { let monthValidate = pr.getMonth() return monthValidate > 5 ? pr.getFullYear() + 1 : pr.getFullYear() } console.log(getGroupQuarter(quarters1, periods1)); console.log(getGroupQuarter(quarters, periods));

Answer 2

假設一個時期內沒有差距——即屬於同一時期的兩個季度之間沒有差距——你可以應用這個邏輯：

• 當最后一個季度已知時（即等於期末），減去 2 個季度並將該季度的年份作為財政年度
• 如果不知道最后一個季度的周期——這可能發生在數組的開頭，當前周期尚未完成——在該周期的第一季度添加一個季度，並將該季度的年份作為財政年度.

由於將periods組一對一映射以獲得結果數組非常好，因此有時可能需要去除最后一個句點條目（如在測試用例 1 中），或者在該句點的開頭插入一個未完成的句點數組（也在測試用例 1 中）。

不相關，但我避免了此任務的 Date 對象，並包含將輸入字符串轉換為數字並返回的函數：

 function chunkByYear(quarters, periods) { // Converter functions between string and unique quarter number const toQuarter = s => s.match(/^\d+|\d+$/g).reduce((m, y) => m/3 - 1 + y*4); const toDate = q => ((q % 4 + 1)*3 + "/30/" + (q >> 2)).padStart(10, "0"); const periodNums = periods.map(toQuarter); const quarterNums = quarters.map(toQuarter); // Make sure all quarters are after at least one period end while (quarterNums[quarterNums.length-1] <= periodNums[periodNums.length-1]) periodNums.push(periodNums[periodNums.length-1] - 4); // Remove periods that have no content: while (quarterNums[0] <= periodNums[0]) periodNums.shift(); quarterNums.push(0); // To make sure `findIndex` always finds an index return periodNums.map((p, i, {length}) => { const period = quarterNums.splice(0, quarterNums.findIndex(q => q <= p)); return { [(i ? period[0] - 2 : period[period.length-1] + 1) >> 2]: period.map(toDate) }; }); } { // test 1 const quarters = [ "12 / 30 / 2021", "09 / 30 / 2021", "06 / 30 / 2021", "03 / 30 / 2021", "12 / 30 / 2020", "09 / 30 / 2020", "06 / 30 / 2020", "12 / 30 / 2019", "09 / 30 / 2019", "06 / 30 / 2019", "03 / 30 / 2019", "12 / 30 / 2018", "09 / 30 / 2018", "06 / 30 / 2018", "03 / 30 / 2018", ]; const periods = ["03 / 30 / 2021", "12 / 30 / 2019", "12 / 30 / 2018", "12 / 30 / 2017"]; console.log(chunkByYear(quarters, periods)); } { // test 2 const quarters = [ "12 / 30 / 2020", "09 / 30 / 2020", "06 / 30 / 2020", "03 / 30 / 2020", "12 / 30 / 2019", "09 / 30 / 2019", "06 / 30 / 2019", "03 / 30 / 2019", "12 / 30 / 2018" ]; const periods = ["09 / 30 / 2020", "09 / 30 / 2019", "09 / 30 / 2018"]; console.log(chunkByYear(quarters, periods)); } { // test 3 const quarters = [ "06 / 30 / 2021", "03 / 30 / 2021", "12 / 30 / 2020", "09 / 30 / 2020", "06 / 30 / 2020", "03 / 30 / 2020", "12 / 30 / 2019", "09 / 30 / 2019", "06 / 30 / 2019", ]; const periods = ["06 / 30 / 2021", "06 / 30 / 2020", "06 / 30 / 2019"]; console.log(chunkByYear(quarters, periods)); } { // test 4 const quarters = [ "06 / 30 / 2021", "03 / 30 / 2021", "12 / 30 / 2020", "09 / 30 / 2020", "06 / 31 / 2020", "03 / 30 / 2020", "12 / 30 / 2019", "09 / 30 / 2019", "06 / 30 / 2019", "03 / 30 / 2019", "12 / 30 / 2018", "09 / 30 / 2018", ]; const periods = ["06 / 30 / 2021", "06 / 31 / 2020", "06 / 30 / 2019"]; console.log(chunkByYear(quarters, periods)); }