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[英]std::future: Async single producer + any number of consumers problem
[英]Is there any potential problem in the code snippet below if `std::future::get()` would not be called?
如果不調用std::future::get()
,下面的代碼片段中是否存在任何潛在問題?
我做了幾個測試。 似乎上述代碼在不調用std::future::get()
的情況下運行良好,即使std::async
需要很長時間才能完成其工作。 真是出乎我的意料。
#include<future>
#include<iostream>
#include<array>
#include<algorithm>
#include<thread>
#include<vector>
std::array<int, 100000> arr;
int sum=0;
struct Wrapper
{
void consume()
{
std::cout << "consumer:" << std::this_thread::get_id() << std::endl;
std::for_each(arr.begin(), arr.end(), [](int val) {sum+=val; });
}
void produce()
{
std::cout << "producer:" <<std::this_thread::get_id() << std::endl;
int a=0;
while(true)
{
if(a++>1e9)
{
break;
}
}
}
};
int main()
{
std::fill(arr.begin(), arr.end(), 1);
std::cout << "main:" <<std::this_thread::get_id() << std::endl;
Wrapper wrap;
std::vector<std::future<void>> vec;
vec.push_back(std::async(std::launch::async, &Wrapper::produce, &wrap));
vec.push_back(std::async(std::launch::async, &Wrapper::consume, &wrap));
#ifdef WAIT //Is there any potencial problem if the block below does not run?
for(auto& future:vec)
{
future.get();
}
#endif
}
根據有關std::future 析構函數的文檔(強調我的):
這些操作不會阻塞共享狀態准備就緒,除非滿足以下所有條件時可能會阻塞:共享狀態是通過調用 std::async 創建的,共享狀態尚未准備好,並且這是對共享狀態的最后引用。 (C++14 起)
但它似乎只能由C++14
和之后的C++11
保證。
在某些情況下,仍然需要顯式調用std::future::get()
,例如:
#include<future>
#include<iostream>
#include<array>
#include<algorithm>
#include<thread>
#include<vector>
std::array<int, 100000> arr;
int sum=0;
struct Wrapper
{
void consume()
{
std::cout << "consumer:" << std::this_thread::get_id() << std::endl;
std::for_each(arr.begin(), arr.end(), [](int val) {sum+=val; });
}
void produce()
{
std::cout << "producer:" <<std::this_thread::get_id() << std::endl;
int a=0;
while(true)
{
if(a++>1e9)
{
break;
}
}
}
};
int main()
{
std::fill(arr.begin(), arr.end(), 1);
std::cout << "main:" <<std::this_thread::get_id() << std::endl;
Wrapper wrap;
std::vector<std::future<void>> vec;
vec.push_back(std::async(std::launch::async, &Wrapper::produce, &wrap));
vec.push_back(std::async(std::launch::async, &Wrapper::consume, &wrap));
std::cout << sum << std::endl;
#if 1
for(auto& future:vec)
{
future.get();
}
#endif
std::cout << sum << std::endl;
}
以下是上述代碼片段的輸出:
main:140198225385280
0
producer:140198225381120
consumer:140198216988416
100000
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