這個 Python 代碼基本上提示用戶輸入他們的有效電話號碼，並嘗試為電話號碼中的每個數字生成等效的單詞

Question

編譯器在運行時吐出 KeyError: '9'。 有人可以幫我從這段代碼中省略上述錯誤嗎？ 提前致謝！

phone = input("Phone: ")
if len(phone) < 10:
    print("Phone number should be at least 10 digit long!")
else:
    li = []
    for item in range(0, 10, 1):
        li.append(phone[item])
print(li)
word_num = {
     0: "Zero",
     1: "One",
     2: "Two",
     3: "Three",
     4: "Four",
     5: "Five",
     6: "Six",
     7: "Seven",
     8: "Eight",
     9: "Nine"
}
for item in li:
    print(word_num[int(item)])

Answer 1

因為電話號碼中的字符是字符串，所以字典鍵必須是字符串：

word_num = {
     "0": "Zero",
     "1": "One",
     "2": "Two",
     "3": "Three",
     "4": "Four",
     "5": "Five",
     "6": "Six",
     "7": "Seven",
     "8": "Eight",
     "9": "Nine"
}

您的代碼中還有其他問題。 最后一個 for 循環應該是：

for item in li:
    print(word_num[item])

此外，如果電話號碼長度小於 10，則需要停止代碼執行，否則程序會嘗試打印尚不存在的li 。

Answer 2

word_num的鍵為int ，但您試圖以word_num['0']而不是word_num[0]的形式訪問它們。 此外，最后一個for循環應該是：

for item in li:

for item in range(0, 10, 1):的for循環可以重寫為：

for item in range(10):

更正的代碼

phone = input("Phone: ")
if len(phone) < 10:
    print("Phone number should be at least 10 digit long!")
else:
    li = []
    for item in range(10):
        li.append(phone[item])
    print(li)
    word_num = {
        0: "Zero",
        1: "One",
        2: "Two",
        3: "Three",
        4: "Four",
        5: "Five",
        6: "Six",
        7: "Seven",
        8: "Eight",
        9: "Nine"
    }
    for item in li:
        print(word_num[int(item)])  # convert item to int

---

樣本輸出

Phone: 0123456789 
['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']
Zero
One
Two
Three
Four
Five
Six
Seven
Eight
Nine

編輯 1：如果輸入少於 10 個字符，則什么也不做。

Answer 3

您的代碼有很多問題。 您需要確保作為phone一部分輸入的每個字符實際上都是一個數字。 然后您必須將字符串值轉換為 int 才能使用它來索引word_num 。 最后，如果用戶輸入的內容少於 10 個字符，您會因為li未初始化而失敗。

import re

while True:
    phone = input("Phone: ")
    if len(phone) >= 10 and re.fullmatch(r'[0-9]+', phone):
        break
    print("Phone number should be at least 10 digit long!")

li = [int(d) for d in phone]
print(li)
word_num = {
     0: "Zero",
     1: "One",
     2: "Two",
     3: "Three",
     4: "Four",
     5: "Five",
     6: "Six",
     7: "Seven",
     8: "Eight",
     9: "Nine"
}
for item in li:
    print(word_num[item])

樣品運行：

Phone: aaa
Phone number should be at least 10 digit long!
Phone: a012349499595
Phone number should be at least 10 digit long!
Phone: 1234567890
[1, 2, 3, 4, 5, 6, 7, 8, 9, 0]
One
Two
Three
Four
Five
Six
Seven
Eight
Nine
Zero

Answer 4

如果您在程序開始時定義“li”，那么它就可以正常工作。
我無法粘貼代碼，所以這里有一個鏈接001.py

Answer 5

你需要像這樣重寫最后一個for循環

for item in li:
    print(word_num[item])