空手道 - 有沒有辦法獲取當前功能文件的名稱

Question

我想對下面的功能文件做一個簡單的調整：

@Read @healthCheck
Feature: healthCheck
  Background:
    * def service = "healthCheck"
    * def req = call read("classpath:SoapRequest.feature")

  Scenario: toggle healthcheck
    Given match each /Envelope/Body/pingResponse/healthChecks/healthCheck/status == "SUCCESS"

類似於：

@Read @healthCheck
Feature: healthCheck
  Background:
    * def service = //name of this feature
    * def req = call read("classpath:SoapRequest.feature")

  Scenario: toggle healthcheck
    Given match each /Envelope/Body/pingResponse/healthChecks/healthCheck/status == "SUCCESS"

為了避免重復輸入的錯誤，有沒有相關的用法？

Answer 1

看看這是否有效：

* def service = karate.feature.fileName

參考： https ://github.com/karatelabs/karate/wiki/1.0-upgrade-guide#karateinfo-deprecated

如果它不起作用，您可能需要貢獻代碼。