用字母和數字在字典列表中排序

Question

我有一個要排序的字典列表。 這是我到目前為止所擁有的：

output_list = [{'mac': '0123.4567.89ab', 'port': 'Gi1/0/10'},
               {'mac': '0123.4567.89ab', 'port': 'Gi1/0/1'},
               {'mac': '0123.4567.89ab', 'port': 'Gi1/0/5'},
               {'mac': '0123.4567.89ab', 'port': 'Gi1/0/48'},
               {'mac': '0123.4567.89ab', 'port': 'Gi2/0/1'},
               {'mac': '0123.4567.89ab', 'port': 'Gi1/0/6'},
               {'mac': '0123.4567.89ab', 'port': 'Gi2/0/4'},
               {'mac': '0123.4567.89ab', 'port': 'Gi2/0/13'},
               {'mac': '0123.4567.89ab', 'port': 'Gi8/0/9'},
               {'mac': '0123.4567.89ab', 'port': 'Gi8/0/8'},
               {'mac': '0123.4567.89ab', 'port': 'Te1/1/1'}]

mac_list = sorted(output_list, key=lambda d: "/".join([x for x in d['port'].split("/")]))

pprint(mac_list)

但是，它並沒有按照我想要的方式對字典進行排序。

"C:\Program Files\Python310\python.exe" "C:/Scripts/Python/test1.py"
[{'mac': '0123.4567.89ab', 'port': 'Gi1/0/1'},
 {'mac': '0123.4567.89ab', 'port': 'Gi1/0/10'},
 {'mac': '0123.4567.89ab', 'port': 'Gi1/0/48'},
 {'mac': '0123.4567.89ab', 'port': 'Gi1/0/5'},
 {'mac': '0123.4567.89ab', 'port': 'Gi1/0/6'},
 {'mac': '0123.4567.89ab', 'port': 'Gi2/0/1'},
 {'mac': '0123.4567.89ab', 'port': 'Gi2/0/13'},
 {'mac': '0123.4567.89ab', 'port': 'Gi2/0/4'},
 {'mac': '0123.4567.89ab', 'port': 'Gi8/0/8'},
 {'mac': '0123.4567.89ab', 'port': 'Gi8/0/9'},
 {'mac': '0123.4567.89ab', 'port': 'Te1/1/1'}]

Process finished with exit code 0

我怎樣才能讓它排序它看起來像這樣：

[{'mac': '0123.4567.89ab', 'port': 'Gi1/0/1'},
 {'mac': '0123.4567.89ab', 'port': 'Gi1/0/5'},
 {'mac': '0123.4567.89ab', 'port': 'Gi1/0/6'},
 {'mac': '0123.4567.89ab', 'port': 'Gi1/0/10'},
 {'mac': '0123.4567.89ab', 'port': 'Gi1/0/48'},
 {'mac': '0123.4567.89ab', 'port': 'Gi2/0/1'},
 {'mac': '0123.4567.89ab', 'port': 'Gi2/0/4'},
 {'mac': '0123.4567.89ab', 'port': 'Gi2/0/13'},
 {'mac': '0123.4567.89ab', 'port': 'Gi8/0/8'},
 {'mac': '0123.4567.89ab', 'port': 'Gi8/0/9'},
 {'mac': '0123.4567.89ab', 'port': 'Te1/1/1'}]

Answer 1

嘗試：

out = sorted(
    output_list,
    key=lambda d: (d["port"][:2], *map(int, d["port"][2:].split("/"))),
)

print(out)

印刷：

[
    {"mac": "0123.4567.89ab", "port": "Gi1/0/1"},
    {"mac": "0123.4567.89ab", "port": "Gi1/0/5"},
    {"mac": "0123.4567.89ab", "port": "Gi1/0/6"},
    {"mac": "0123.4567.89ab", "port": "Gi1/0/10"},
    {"mac": "0123.4567.89ab", "port": "Gi1/0/48"},
    {"mac": "0123.4567.89ab", "port": "Gi2/0/1"},
    {"mac": "0123.4567.89ab", "port": "Gi2/0/4"},
    {"mac": "0123.4567.89ab", "port": "Gi2/0/13"},
    {"mac": "0123.4567.89ab", "port": "Gi8/0/8"},
    {"mac": "0123.4567.89ab", "port": "Gi8/0/9"},
    {"mac": "0123.4567.89ab", "port": "Te1/1/1"},
]

---

筆記：

(d["port"][:2], *map(int, d["port"][2:].split("/")))將以('Gi', 1, 0, 48)等等。 sorted()函數將根據這些元組進行排序。

Answer 2

嘗試這個：

mac_list = sorted(output_list, key=lambda d: tuple(int(x) if x.isdigit() else x for x in d['port'].split("/")))

這會將數字字符串轉換為split()生成的port值的子字符串中的int值，並將非數字字符串保持原樣，並且基於結果tuple值的排序將為您提供所需的輸出。

Answer 3

似乎您正在尋找人類/自然排序。 這個答案很好地涵蓋了它。

使用該答案中的natural_keys函數，然后可以將端口字符串直接傳遞給定義的函數，如下所示：

output_list.sort(key=lambda d: natural_keys(d["port"]))