你如何比較兩個 Ansible 列表中的值？

Question

我在 Ansible 中有兩個列表，我使用find模塊即時構建

- name: "Find all files in {{ backup_path }}"
  ansible.builtin.find:
    paths:
      - "{{ backup_path }}"
    get_checksum: true
    recurse: yes
    depth: 2
    patterns: "{{ file_patterns }}"
  register: backup_files

- name: "Find all files in {{ new_path }}"
  ansible.builtin.find:
    paths:
      - "{{ new_path }}"
    get_checksum: true
    recurse: yes
    depth: 2
    patterns: "{{ file_patterns }}"
  register: new_files

一旦我注冊了這些變量，我想在old_files和new_files列表之間運行一個差異。

- name: diff files between new and old
  ansible.builtin.shell: 
    cmd: "diff {{ item.0 }} {{ item.1 }}"
  register: diff_files
  loop: 
    - "{{ backup_files }}"
    - "{{ new_files }}"

我知道上面的代碼片段是錯誤的，但我想將 new_files 中的第 0 項與 old_files 中的第 0 項進行 n 次比較。

本 playbook 的目的是比較兩個目錄中的所有文件並替換不同的文件。

Answer 1

事實證明，我讓這變得比它需要的復雜得多，這是更簡單的工作。 基本上，使用diff -rq \path1 \path2 。

- name: diff conf files between new and old
  ansible.builtin.shell: 
    cmd: "diff -rq {{ new_path }}conf {{ backup_path }}conf"
  register: diff_conf_files
  failed_when: diff_conf_files.rc not in [0,1]
  ignore_errors: yes

- name: diff bin files between new and old
  ansible.builtin.shell: 
    cmd: "diff -rq {{ new_path }}bin {{ backup_path }}bin"
  register: diff_bin_files
  failed_when: diff_bin_files.rc not in [0,1]
  ignore_errors: yes