登錄后如何打印用戶名等數據[php-codeigniter]

Question

我嘗試打印用戶 ID，它可以工作，但是當我嘗試打印用戶名時，我嘗試了來自網絡的不同方法，但對我沒有任何效果。 有人可以幫我打印用戶名：D

看起來像這樣：它顯示了什么

看法：

<h1>Hi <?php echo $_SESSION['user_id'];?></h1>
    <h1>Hi <?php echo $_SESSION['username'];?></h1>

控制器：

<?php
defined('BASEPATH') OR exit('No direct script access allowed');

class Login extends CI_Controller {

    public function index()
    {
        if (isset($_SESSION['user_id'])){
            redirect("admin/dashboard");
        }
        $data=[];
        if (isset($_SESSION['error'])){
            $data['error']=$_SESSION['error'];
        }else{
            $data['error']="NO_ERROR";
        }
        $this->load->view('adminpanel/loginview',$data);
    }
    function login_post(){
        print_r($_POST);
        if (isset($_POST)){
            $email=$_POST['email'];
            $password=$_POST['password'];

            $query = $this->db->query("SELECT * FROM `backenduser` WHERE `username`='$email' AND `password`='$password'");

            if ($query->num_rows()){
                $result= $query->result_array();
                //echo"<pre>";
                //print_r($result);
                **$this->session->set_userdata('user_id',$result[0]['uid']);
                $_SESSION['username']=$result->username;**
                redirect('admin/dashboard');
            }else{
                $this->session->set_flashdata('error','Invalid Credentials');
                redirect('admin/login');
            }
        }else{
            die("invalid input!");
        }
    }
}

Answer 1

你可以試試這個。

<?php
defined('BASEPATH') OR exit('No direct script access allowed');

class Login extends CI_Controller {

public function index()
{
    if (isset($_SESSION['user_id'])){
        redirect("admin/dashboard");
    }
    $data=[];
    if (isset($_SESSION['error'])){
        $data['error']=$_SESSION['error'];
    }else{
        $data['error']="NO_ERROR";
    }
    $this->load->view('adminpanel/loginview',$data);
}
function login_post(){
    print_r($_POST);
    if (isset($_POST)){
        $email=$_POST['email'];
        $password=$_POST['password'];

        $query = $this->db->query("SELECT * FROM `backenduser` WHERE `username`='$email' AND `password`='$password'");

        if ($query->num_rows()){
            $result= $query->result_array();
            //echo"<pre>";
            //print_r($result);
        

            $session_data = array(
                    'user_id' => $result[0]['uid'],
                    'username' => $result->username,
                 
                );
                $this->session->set_userdata($session_data);

            redirect('admin/dashboard');
        }else{
            $this->session->set_flashdata('error','Invalid Credentials');
            redirect('admin/login');
        }
    }else{
        die("invalid input!");
    }
}
}

Answer 2

假設：-您在 $result 變量中獲取用戶數據與獲取 id 相同

function login_post(){
print_r($_POST);
if (isset($_POST)){
    $email=$_POST['email'];
    $password=$_POST['password'];

    $query = $this->db->query("SELECT * FROM `backenduser` WHERE `username`='$email' AND `password`='$password'");

    if ($query->num_rows()){
        $result= $query->result_array();
        //echo"<pre>";
        //print_r($result);
    

        $session_data = array(
                'user_id' => $result[0]['uid'],
                'username' => $result[0]['username'],
             
            );
            $this->session->set_userdata($session_data);

        redirect('admin/dashboard');
    }else{
        $this->session->set_flashdata('error','Invalid Credentials');
        redirect('admin/login');
    }
}else{
    die("invalid input!");
}