如何從列表列表中創建字典並對其進行排序？

Question

請告訴我如何從現有列表中創建字典：

my_list = [[['id_1', 'A', 10], ['id_1', 'C', 3], ['id_1', 'B', 2]],
          [['id_2', 'E', 4], ['id_2', 'A', 3], ['id_2', 'D', 1]],
          [['id_3', 'B', 3], ['id_3', 'C', 1]],
          [['id_4', 'E', 10], ['id_4', 'A', 5], ['id_4', 'B', 4], ['id_4', 'F', 2]]]

我需要這樣的字典：

dictionary = {'A': [('id_1', 10 ), ('id_4', 5), ('id_2', 3)],
              'B': [('id_4', 4), ('id_3', 3), ('id_1', 2)],
              'C': [('id_1', 3), ('id_3', 1)],
              'D': [('id_2', 1)],
              'E': [('id_4', 10), ('id_2', 4)],
              'F': [('id_4', 2)]
              }

謝謝您的幫助！

Answer 1

你可以只使用嵌套循環..

my_dict = {}
for i in my_list:
    for j in i:
        try: 
            my_dict[j[1]] += [(j[0], j[-1])]
        except KeyError: 
            my_dict[j[1]] = [(j[0], j[-1])]
my_dict = dict(sorted(my_dict.items()))
my_dict

----------------------------------------------------
{'A': [('id_1', 10), ('id_2', 3), ('id_4', 5)],
 'B': [('id_1', 2), ('id_3', 3), ('id_4', 4)],
 'C': [('id_1', 3), ('id_3', 1)],
 'D': [('id_2', 1)],
 'E': [('id_2', 4), ('id_4', 10)],
 'F': [('id_4', 2)]}
----------------------------------------------------

Answer 2

你可以試試這個：

my_list = [[['id_1', 'A', 10], ['id_1', 'C', 3], ['id_1', 'B', 2]],
          [['id_2', 'E', 4], ['id_2', 'A', 3], ['id_2', 'D', 1]],
          [['id_3', 'B', 3], ['id_3', 'C', 1]],
          [['id_4', 'E', 10], ['id_4', 'A', 5], ['id_4', 'B', 4], ['id_4', 'F', 2]]]

flattened = [item for sublist in my_list for item in sublist]

my_dict = {}

for _id, ltr, num in flattened:
    if ltr in my_dict: # changed from my_dict.keys()
        my_dict[ltr].append((_id, num))
    else:
        my_dict[ltr] = [(_id, num)]

sorted_dict = dict(sorted(my_dict.items()))

print(sorted_dict)

---

如果你想知道，這就是flattened 、 my_dict和sorted_dict的樣子：

flattened = [
    ['id_1', 'A', 10], ['id_1', 'C', 3], ['id_1', 'B', 2],
    ['id_2', 'E', 4], ['id_2', 'A', 3], ['id_2', 'D', 1],
    ['id_3', 'B', 3], ['id_3', 'C', 1], ['id_4', 'E', 10],
    ['id_4', 'A', 5], ['id_4', 'B', 4], ['id_4', 'F', 2]
]

my_dict = {
    'A': [('id_1', 10), ('id_2', 3), ('id_4', 5)],
    'C': [('id_1', 3), ('id_3', 1)],
    'B': [('id_1', 2), ('id_3', 3), ('id_4', 4)],
    'E': [('id_2', 4), ('id_4', 10)],
    'D': [('id_2', 1)],
    'F': [('id_4', 2)]
}

sorted_dict = {
    'A': [('id_1', 10 ), ('id_4', 5), ('id_2', 3)],
    'B': [('id_4', 4), ('id_3', 3), ('id_1', 2)],
    'C': [('id_1', 3), ('id_3', 1)],
    'D': [('id_2', 1)],
    'E': [('id_4', 10), ('id_2', 4)],
    'F': [('id_4', 2)]
}

Answer 3

從defaultdict開始並從my_list ，然后排序。

from collections import defaultdict

my_list = [[['id_1', 'A', 10], ['id_1', 'C', 3], ['id_1', 'B', 2]],
          [['id_2', 'E', 4], ['id_2', 'A', 3], ['id_2', 'D', 1]],
          [['id_3', 'B', 3], ['id_3', 'C', 1]],
          [['id_4', 'E', 10],['id_4', 'A', 5],['id_4', 'B', 4], ['id_4', 'F', 2]]]

d = defaultdict(list) 
[d[i[1]].append((i[0],i[2])) for j in my_list for i in j]
dictionary = dict(sorted(d.items()))