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[英]mysql query returns zero rows in SQL query even though it is in the database
[英]SQL query returns zero rows
我必須為每個用戶查找加入日期以及他們作為買家在 2019 年下的訂單數量。
Table: Users
+----------------+---------+
| Column Name | Type |
+----------------+---------+
| user_id | int |
| join_date | date |
| favorite_brand | varchar |
+----------------+---------+
user_id 是該表的主鍵。 此表包含在線購物網站的用戶信息,用戶可以在該網站上銷售和購買商品。
表:訂單
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| order_id | int |
| order_date | date |
| item_id | int |
| buyer_id | int |
| seller_id | int |
+---------------+---------+
order_id 是該表的主鍵。 item_id 是 Items 表的外鍵。 買家 ID 和賣家 ID 是用戶表的外鍵。
表:項目
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| item_id | int |
| item_brand | varchar |
+---------------+---------+
item_id is the primary key of this table.
輸入:
用戶表:
+---------+------------+----------------+
| user_id | join_date | favorite_brand |
+---------+------------+----------------+
| 1 | 2018-01-01 | Lenovo |
| 2 | 2018-02-09 | Samsung |
| 3 | 2018-01-19 | LG |
| 4 | 2018-05-21 | HP |
+---------+------------+----------------+
訂單表:
+----------+------------+---------+----------+-----------+
| order_id | order_date | item_id | buyer_id | seller_id |
+----------+------------+---------+----------+-----------+
| 1 | 2019-08-01 | 4 | 1 | 2 |
| 2 | 2018-08-02 | 2 | 1 | 3 |
| 3 | 2019-08-03 | 3 | 2 | 3 |
| 4 | 2018-08-04 | 1 | 4 | 2 |
| 5 | 2018-08-04 | 1 | 3 | 4 |
| 6 | 2019-08-05 | 2 | 2 | 4 |
+----------+------------+---------+----------+-----------+
物品表:
+---------+------------+
| item_id | item_brand |
+---------+------------+
| 1 | Samsung |
| 2 | Lenovo |
| 3 | LG |
| 4 | HP |
+---------+------------+
輸出:
+-----------+------------+----------------+
| buyer_id | join_date | orders_in_2019 |
+-----------+------------+----------------+
| 1 | 2018-01-01 | 1 |
| 2 | 2018-02-09 | 2 |
| 3 | 2018-01-19 | 0 |
| 4 | 2018-05-21 | 0 |
+-----------+------------+----------------+
我寫了以下解決方案,但它不起作用。 請解釋它有什么問題。
select u.user_id as buyer_id, u.join_date as join_date, count(o.order_id) as orders_in_2019
from Users u join Orders o on u.user_id = o.buyer_id
where o.order_date < date('2010-01-01') and o.order_date >= date('2019-01-01')
group by u.user_id;
這給了我空的結果。
除了日期錯字(o.order_date < '2010-01-01')之外,您似乎希望所有用戶即使他們在 2019 年沒有訂單,所以左連接和條件聚合似乎是合適的
select u.user_id as buyer_id, u.join_date as join_date
,sum(case when o.order_date < '2020-01-01' and o.order_date >= '2019-01-01' then 1 else 0 end) cnt
from users u
left join Orders o on u.user_id = o.buyer_id
group by u.user_id ;
+----------+------------+------+
| buyer_id | join_date | cnt |
+----------+------------+------+
| 1 | 2018-01-01 | 1 |
| 2 | 2018-02-09 | 2 |
| 3 | 2018-01-19 | 0 |
| 4 | 2018-05-21 | 0 |
+----------+------------+------+
4 rows in set (0.001 sec)
您無法通過關閉選擇不在組中的直接元素
select g_user.buyer_id, Users.join_date as join_date , g_user.orders_in_2019 From (select u.user_id as buyer_id, count(o.order_id) as orders_in_2019 From Users u
join Orders o on u.user_id = o.buyer_id
where o.order_date < date('2010-01-01') and o.order_date >= date('2019-01-01')
group by u.user_id)
as g_user join Users on g_user.buyer_id = Users.user_id;
這是因為您的日期在 sql 中不正確:
o.order_date < date('2010-01-01')
很明顯,您的訂單都不是在 2010 年之前。您應該更改為
o.order_date < date('2020-01-01')
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