Oracle SQL 查詢兩個日期之間的鍛煉天數

Question

我需要有關 SQL 查詢的幫助，該查詢將生成 Start_date 和 End_Date 之間的星期幾並使用工作日。

示例：日歷 99 的開始日期和結束日期之間需要是工作日“星期三”起點 (seqnum 1) 和工作日星期六 (seqnum2) 的日期。

簡而言之，兩個日期之間的星期日期取決於日歷和工作日以及要生產的順序的 seqnum。

任何幫助或想法將不勝感激。

CREATE TABLE CALENDAR
(
  CALENDAR_NAME  VARCHAR2(500 CHAR),
  START_DATE     VARCHAR2(100 CHAR),
  END_DATE       VARCHAR2(100 CHAR),
  SEQNUM         NUMBER,
  WEEKDAY        VARCHAR2(9 CHAR),
  STARTTIME      VARCHAR2(8 CHAR)
);

Insert into SCPOMGR.UDT_CALENDAR
   (CALENDAR_NAME, START_DATE, END_DATE, SEQNUM, WEEKDAY, 
    STARTTIME)
 Values
   ('99', '2020-07-29', '2021-08-07', 1, 'WEDNESDAY', 
    '17:00:00');
Insert into SCPOMGR.UDT_CALENDAR
   (CALENDAR_NAME, START_DATE, END_DATE, SEQNUM, WEEKDAY, 
    STARTTIME)
 Values
   ('99', '2020-07-29', '2021-08-07', 2, 'SATURDAY', 
    '17:00:00');
Insert into SCPOMGR.UDT_CALENDAR
   (CALENDAR_NAME, START_DATE, END_DATE, SEQNUM, WEEKDAY, 
    STARTTIME)
 Values
   ('179', '2000-01-02', '2021-02-01', 1, 'MONDAY', 
    '18:00:00');
Insert into SCPOMGR.UDT_CALENDAR
   (CALENDAR_NAME, START_DATE, END_DATE, SEQNUM, WEEKDAY, 
    STARTTIME)
 Values
   ('179', '2000-01-02', '2021-02-01', 2, 'WEDNESDAY', 
    '18:00:00');
Insert into SCPOMGR.UDT_CALENDAR
   (CALENDAR_NAME, START_DATE, END_DATE, SEQNUM, WEEKDAY, 
    STARTTIME)
 Values
   ('179', '2000-01-02', '2021-02-01', 3, 'FRIDAY', 
    '18:00:00');
Insert into SCPOMGR.UDT_CALENDAR
   (CALENDAR_NAME, START_DATE, END_DATE, SEQNUM, WEEKDAY, 
    STARTTIME)
 Values
   ('179', '2000-01-02', '2021-02-01', 4, 'SUNDAY', 
    '18:00:00');
Insert into SCPOMGR.UDT_CALENDAR
   (CALENDAR_NAME, START_DATE, END_DATE, SEQNUM, WEEKDAY, 
    STARTTIME)
 Values
   ('772', '2000-01-02', '2021-02-01', 1, 'TUESDAY', 
    '18:00:00');
Insert into SCPOMGR.UDT_CALENDAR
   (CALENDAR_NAME, START_DATE, END_DATE, SEQNUM, WEEKDAY, 
    STARTTIME)
 Values
   ('772', '2000-01-02', '2021-02-01', 2, 'WEDNESDAY', 
    '18:00:00');
Insert into SCPOMGR.UDT_CALENDAR
   (CALENDAR_NAME, START_DATE, END_DATE, SEQNUM, WEEKDAY, 
    STARTTIME)
 Values
   ('772', '2000-01-02', '2021-02-01', 3, 'THURSDAY', 
    '18:00:00');
Insert into SCPOMGR.UDT_CALENDAR
   (CALENDAR_NAME, START_DATE, END_DATE, SEQNUM, WEEKDAY, 
    STARTTIME)
 Values
   ('772', '2000-01-02', '2021-02-01', 4, 'FRIDAY', 
    '18:00:00');
Insert into SCPOMGR.UDT_CALENDAR
   (CALENDAR_NAME, START_DATE, END_DATE, SEQNUM, WEEKDAY, 
    STARTTIME)
 Values
   ('772', '2000-01-02', '2021-02-01', 5, 'SATURDAY', 
    '18:00:00');
Insert into SCPOMGR.UDT_CALENDAR
   (CALENDAR_NAME, START_DATE, END_DATE, SEQNUM, WEEKDAY, 
    STARTTIME)
 Values
   ('772', '2000-01-02', '2021-02-01', 6, 'SUNDAY', 
    '18:00:00');
Insert into SCPOMGR.UDT_CALENDAR
   (CALENDAR_NAME, START_DATE, END_DATE, SEQNUM, WEEKDAY, 
    STARTTIME)
 Values
   ('772', '2000-01-02', '2021-02-01', 7, 'MONDAY', 
    '18:00:00');
COMMIT;

Answer 1

簡而言之，兩個日期之間的星期日期取決於日歷和工作日以及要生產的順序的 seqnum。

如果這被解釋為，對於每個calendar_name ，您希望從start_date開始並輸出與每周的weekday匹配的星期幾，直到您到達end_date 。

注意：如果將日期存儲在日期數據類型中會更好。

您可以使用遞歸子查詢：

WITH dates (calendar_name, dt, end_date) AS (
  SELECT calendar_name,
         NEXT_DAY(TO_DATE(start_date, 'YYYY-MM-DD') - INTERVAL '1' DAY, weekday),
         TO_DATE(end_date, 'YYYY-MM-DD')
  FROM   calendar
  WHERE  NEXT_DAY(TO_DATE(start_date, 'YYYY-MM-DD') - INTERVAL '1' DAY, weekday)
           <= TO_DATE(end_date, 'YYYY-MM-DD')
UNION ALL
  SELECT calendar_name,
         dt + INTERVAL '7' DAY,
         end_date
  FROM   dates
  WHERE  dt + INTERVAL '7' DAY <= end_date
)
SELECT calendar_name,
       dt
FROM   dates
ORDER BY
       calendar_name,
       dt

db<> 在這里擺弄