[英]In TypeScript, how to convert all types within a Union to an array of that type
假設我有以下內容：
type UnionType = CustomType1 | CustomType2 | CustomType3;
// is there a way to accomplish this, without having to type it out like so.
type UnionTypeArr = CustomType1[] | CustomType2[] | CustomType3[];
您可以使用分布式條件類型（ T extends X ? Y : Z形式的條件類型，其中T是泛型類型參數）將聯合拆分為其成員，對每個成員執行轉換，並將結果組合到另一個聯盟：
type DistribArrayify<T> = T extends unknown ? Array<T> : never;
type UnionType = CustomType1 | CustomType2 | CustomType3;
type UnionTypeArr = DistribArrayify<UnionType>;
// type UnionTypeArr = CustomType1[] | CustomType2[] | CustomType3[]
Typescript：如何將鍵數組轉換為聯合類型的對象？
[英]Typescript: How to convert an array of keys into a union type of objects?
轉換打字稿中的聯合類型以綁定內部類型，而不是所有類型
[英]Transforming union types in typescript to bind inner type, instead of all types
為什么 TypeScript 會為具有數組類型聯合的數組項推斷此類型？
[英]Why does TypeScript infer this type for the array item with a union of array types?
打字稿我想要一個類型，它是所有類型的聯合屬性
[英]Typescript I want a type which is the union of all types in an abject properties
如何鍵入接收通用聯合類型數組的遞歸 function？ （打字稿）
[英]How do I type a recursive function receiving an array of generic union types? (typescript)
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