將python字典基本長度的值排序為列表

Question

我有一個 python 字典，其值為整數列表。 我想根據列表值的長度按降序對其進行排序

_dict = {
         'owner_1': [320, 203, 123, 32, 923, 12398], 
         'owner_2': [239, 90, 3423, 234, 3994, 93294, 923849, 939, 312, 2341, 93, 
                    9244, 294, 939532, 9284, 9113, 34, 98934, 9293, 83], 
         'owner_3': [2399, 934, 8231, 921338, 9394, 9023, 92, 911, 934, 983912, 
                    9219, 239, 9021092, 9294]
         }

輸出應該像

_dict = {
         'owner_2': [239, 90, 3423, 234, 3994, 93294, 923849, 939, 312, 2341, 93, 
                     9244, 294, 939532, 9284, 9113, 34, 98934, 9293, 83], 
         'owner_3': [2399, 934, 8231, 921338, 9394, 9023, 92, 911, 934, 983912, 
                     9219, 239, 9021092, 9294], 
         'owner_1': [320, 203, 123, 32, 923, 12398]
         }

Answer 1

您可以在dict.items()上使用sorted並使用len作為dict的value 。

>>> dict(sorted(_dict.items(), key=lambda x: len(x[1]), reverse=True))
# --------------------------------------x[0] is key, x[1] is value of each item dict
{
    'owner_2': [239, 90, 3423, 234, 3994, 93294, 923849, 939, 312, 2341, 93, 9244, 294, 939532, 9284, 9113, 34, 98934, 9293, 83], 
    'owner_3': [2399, 934, 8231, 921338, 9394, 9023, 92, 911, 934, 983912, 9219, 239, 9021092, 9294], 
    'owner_1': [320, 203, 123, 32, 923, 12398]
}

Answer 2

_dict = {
         'owner_1': [320, 203, 123, 32, 923, 12398], 
         'owner_2': [239, 90, 3423, 234, 3994, 93294, 923849, 939, 312, 2341, 93, 
                    9244, 294, 939532, 9284, 9113, 34, 98934, 9293, 83], 
         'owner_3': [2399, 934, 8231, 921338, 9394, 9023, 92, 911, 934, 983912, 
                    9219, 239, 9021092, 9294]
         }
    

sorted_dict = {}
for k in sorted(_dict, key=lambda k: len(_dict[k]), reverse=True):
    sorted_dict[k] = _dict[k]
    
print(sorted_dict)

Answer 3

使用 short() 函數來解決這個問題

Answer 4

_dict = {
         'owner_1': [320, 203, 123, 32, 923, 12398], 
         'owner_2': [239, 90, 3423, 234, 3994, 93294, 923849, 939, 312, 2341, 93, 
                    9244, 294, 939532, 9284, 9113, 34, 98934, 9293, 83], 
         'owner_3': [2399, 934, 8231, 921338, 9394, 9023, 92, 911, 934, 983912, 
                    9219, 239, 9021092, 9294]
         }


{key:value for key,value in sorted(_dict.items(), key = lambda x: len(x[1]), reverse=True)}

這是根據值對字典進行排序的單行器。 鍵是 x[0]（'owner_1'、'owner_2' 等），值是 x[1] 的長度或與鍵對應的列表中的項目數。 最后 reverse= True 以相反的順序打印字典。