如何將 Array 嵌套對象轉換為 Array 對象？

Question

我有一個數組：

let testData = [
  {
    MC: "11233",
    jobid: 113331,
    list: [
      { Q1: 1113, Q2: 333, code: "thisis1" },
      { Q1: 333, Q2: 111, code: "thisis2" },
      { Q1: 333, code: "thisis3" },
    ],
  },
  {
    MC: "332211",
    jobid: 3333,
    list: [
      { Q1: 444, Q2: 555, code: "thisis4" },
    ],
  },
];

我想把它轉換成：

[
  { MC: "11233", jobid: 113331, Q1: 1113, Q2: 333, code: "thisis1" },
  { MC: "11233", jobid: 113331, Q1: 333, Q2: 111, code: "thisis2" },
  { MC: "11233", jobid: 113331, Q1: 333, code: "thisis3" },
  { MC: "332211", jobid: 3333, Q1: 444, Q2: 555, code: "thisis4" },
]

我試圖寫一個這樣的遞歸函數

let newData = [];
testData.forEach((element, index) => {
  let flattedObj = {};
  deconstructeArrayObject(flattedObj, element);
});

和

const deconstructeArrayObject = (flattedObj, targetObj) => {
  let tempArr = [];
  for (let key in targetObj) {
    if (Array.isArray(targetObj[key])) {
      targetObj[key].forEach((element) => {
        tempArr.push(
          ...JSON.parse(
            JSON.stringify(
              deconstructeArrayObject(flattedObj, element, outputArray)
            )
          )
        );
      });
    } else {
      flattedObj[key] = targetObj[key];
    }
  }
  return flattedObj; // actually I want this function to return an array
};

我不知道我應該如何達到我的目標。 有什么提示或建議嗎？

Answer 1

迭代外部數組， 解構其屬性，然后對每個內部數組執行相同的操作，將所需的數據推送到結果中：

 const input = [ { MC: "11233", jobid: 113331, list: [ { Q1: 1113, Q2: 333, code: "thisis1" }, { Q1: 333, Q2: 111, code: "thisis2" }, { Q1: 333, code: "thisis3" }, ], }, { MC: "332211", jobid: 3333, list: [ { Q1: 444, Q2: 555, code: "thisis4" }, ], }, ]; const result = []; for (const {MC, jobid, list} of input) { for (const {Q1, Q2, code} of list) { result.push(({MC, jobid, Q1, Q2, code})); } } console.log(result);

Answer 2

這個怎么樣：

 let testData = [{"MC":"11233","jobid":113331,"list":[{"Q1":1113, "test": [{ 'a' : 1}, { 'a' : 2}],"Q2":333,"code":"thisis1"},{"Q1":333,"Q2":111,"code":"thisis2"}, {"Q1":333,"code":"thisis3"}]} ,{"MC":"332211","jobid":3333,"list":[{"Q1":444,"Q2":555,"code":"thisis4"}]}] const deconstructeArrayObject = (targetObj) => { let flattedObj = {}; let tempArr = []; let arrayKeys = []; for (let key in targetObj) { // Save array keys if (Array.isArray(targetObj[key])) { arrayKeys.push(key); } else { flattedObj[key] = targetObj[key]; } } // flatten array elements arrayKeys.forEach(key => { targetObj[key].forEach((element) => { const newEl = { ...flattedObj, ...element }; // Recursion const arr = deconstructeArrayObject(newEl); tempArr.push(...arr); }); }); if(tempArr.length === 0) { return [flattedObj]; } return tempArr; } let newData = []; testData.forEach((element, index) => { const result = deconstructeArrayObject(element); newData.push(...result) }); console.log(newData)

結果將是：

[
  {
    "MC": "11233",
    "jobid": 113331,
    "Q1": 1113,
    "Q2": 333,
    "code": "thisis1",
    "a": 1
  },
  {
    "MC": "11233",
    "jobid": 113331,
    "Q1": 1113,
    "Q2": 333,
    "code": "thisis1",
    "a": 2
  },
  {
    "MC": "11233",
    "jobid": 113331,
    "Q1": 333,
    "Q2": 111,
    "code": "thisis2"
  },
  {
    "MC": "11233",
    "jobid": 113331,
    "Q1": 333,
    "code": "thisis3"
  },
  {
    "MC": "332211",
    "jobid": 3333,
    "Q1": 444,
    "Q2": 555,
    "code": "thisis4"
  }
]

Answer 3

這是一個更通用的解決方案，它不依賴於特定的鍵名等。

您缺少的是子問題的答案： how do I merge multiple "deconstructed" objects in an array into my "flattedObj"?

這是通過在下面的函數中調用Object.assign來完成的。

function deconstructeArrayObject(obj) {
  const deconstructedObj = {};
  for (const key in obj) {
    if (Array.isArray(obj[key])) {
      Object.assign(
        deconstructedObj,
        ...obj[key].map(deconstructeArrayObject)
      );
    } else {
      deconstructedObj[key] = obj[key];
    }
  }
  return deconstructedObj;
}

// use like this
let newData = testData.map(deconstructeArrayObject);

Answer 4

你試試這個代碼：

let result = testData.flatMap(data => data.list.map(el => {
    let { list, ...rest } = data;
    return { ...rest, ...el };
}));

Answer 5

您可以使用 Object.assing 並創建扁平化的新對象數組：

 let testData = [ { "MC":"11233", "jobid":113331, "list":[ {"Q1":1113,"Q2":333,"code":"thisis1"}, {"Q1":333,"Q2":111,"code":"thisis2"}, {"Q1":333,"code":"thisis3"} ]}, { "MC":"332211", "jobid":3333, "list":[ {"Q1":444,"Q2":555,"code":"thisis4"} ]} ]; let result = testData.map(d1 => { return d1.list.map(d2 => { return Object.assign({ MC: d1.MC, jobid: d1.jobid }, d2) }); }).flat(); console.log(result);

Answer 6

這是一種使用 flatMap 的方法，它應該返回您需要的內容。

testData.flatMap(job => job.list.map(item => {
  item.MC = job.MC; 
  item.jobid = job.jobid; 
  return item; 
}))