根據條件將 object 復制到另一個

Question

假設我有這個示例 object，如下所示，

let parentObj = {
  "SM": {
    "child_roles": {
      "SM#02": {
        "code": "SM#02",
        "assigned_info": [
          {
            "cur_assigned_to": "7486",
            "assigned_date": 1644483524,
            "assigned_fromdate": 1644517800,
            "assigned_todate": 1645122600,
          },
          {
            "cur_assigned_to": "3050",
            "assigned_date": 1656613800,
            "assigned_fromdate": 1658255400,
            "assigned_todate": 1659292200,
          }
        ]
      },
      "SM#03": {
        "code": "SM#03",
        "assigned_info": [
          {
            "cur_assigned_to": "7486",
            "assigned_date": 1644483638,
            "assigned_fromdate": 1644517800,
            "assigned_todate": 1645727400,
          },
          {
            "cur_assigned_to": "3050",
            "assigned_date": 1656613800,
            "assigned_fromdate": 1656613800,
            "assigned_todate": 1660069800,
          }
        ]
      },
      "SM#01": {
        "code": "SM#01",
        "assigned_info": []
      }
    }
  },
  "SMP": {
    "child_roles": {
      "SMP#01": {
        "code": "SMPR#01",
        "assigned_info": [
          {
            "cur_assigned_to": "7486",
            "assigned_date": 1644483672,
            "assigned_fromdate": 1644431400,
            "assigned_todate": 1645122600,
          }
        ]
      }
    }
  },
  "SMR": {
    "child_roles": {
      "SMR#01": {
        "code": "SMOR#01",
        "assigned_info": []
      },
      "SMOR#02": {
        "code": "SMOR#02",
        "assigned_info": []
      }
    }
  },
  "ANC": {
    "child_roles": {}
  }
}

現在有一個名為assigned_info的鍵，這是一個賦值信息的集合。 我想檢查它是否包含 cur_assigned_to = 3050 的項目，然后復制該數組項目以及該 object 的其他屬性。 對不起我的英語不好，換句話說，我想得到這個 output 如下所示，

let expectedObj = {
  "SM": {
    "child_roles": {
      "SM#02": {
        "code": "SM#02",
        "assigned_info": [
          {
            "cur_assigned_to": "3050",
            "assigned_date": 1656613800,
            "assigned_fromdate": 1658255400,
            "assigned_todate": 1659292200,
          }
        ]
      },
      "SM#03": {
        "code": "SM#03",
        "assigned_info": [
          {
            "cur_assigned_to": "3050",
            "assigned_date": 1656613800,
            "assigned_fromdate": 1656613800,
            "assigned_todate": 1660069800,
          }
        ]
      },
      "SM#01": {
        "code": "SM#01",
        "assigned_info": []
      }
    }
  },
  "SMP": {
    "child_roles": {
      "SMP#01": {
        "code": "SMPR#01",
        "assigned_info": [
        ]
      }
    }
  },
  "SMR": {
    "child_roles": {
      "SMR#01": {
        "code": "SMOR#01",
        "assigned_info": []
      },
      "SMOR#02": {
        "code": "SMOR#02",
        "assigned_info": []
      }
    }
  },
  "ANC": {
    "child_roles": {}
  }
}

我已經嘗試過：我可以遍歷該assigned_info 數組的所有元素並檢查cur_assigned_to 是否為3050，但我無法復制剩余的鍵並且無法刪除其他數組元素。

Answer 1

您可以復制整個parentObj並刪除數組中的意外項目。

let objCopy = JSON.parse(JSON.stringify(parentObj))
for (let i in objCopy) {
    for (let j in objCopy[i]['child_roles']) {
        let obj = objCopy[i]['child_roles'][j]['assigned_info']
        for (let k in obj) {
            if ('cur_assigned_to' in obj[k] && obj[k].cur_assigned_to != '3050') {
                obj.splice(k, 1)
            }
        }
    }
}