如何逐一填充 mongoose 架構

Question

我嘗試填充 mongoose 架構。 我有 3 個模式，分別命名為 ClothBrandSchema、clothSchema、userSchema。

布料品牌架構：

 name: {
    type: String,
    required: true,
  },
  Origin: String,
 }
const ClothBrand = new mongoose.model("ClothBrand", ClothBrandSchema);

第二個是：clothSchema：

{
  category: {
    type: String,
    enum: ["Ladies", "Mens","Kids","Boys","Girls"],
  },
  name: String,
  brand:[{
    type:mongoose.Schema.Types.ObjectId,
    ref:"ClothBrand"
  }]  //many brands have same type of cloth so define array of brands name
}
const Cloth = new mongoose.model("Cloth", clothSchema);

第三個是：userSchema：

{
  name: {
    type: String,
    required: true
  },
    cloth: {
      type:mongoose.Schema.Types.ObjectId,
      ref:"Cloth"
    }
}],
}
const User = new mongoose.model("User", userSchema);

所以我想當我得到用戶的數據然后我得到這樣的：用戶：

{
    "_id": "62df18bdb19a5a056a18c0c9",
     "name": "ABC",
     "cloth": {
          "_id": "62df12525e2c53efd6afe2c5",
           "category": "Boys",
           "name": "Jeans",
           "brand":[  
               {
                "name": "xyz"
                "Origin": "xyz"
               },
               {
                "name": "xyz"
                "Origin": "xyz"
               }
               ...
             ] // somewhere not written an object id so ignore it
         },

那么有沒有可能，那么解決方案是什么。 我如何在我的節點 js 代碼庫中編寫查詢。

Answer 1

我在幾個小時內從 mongoose 官方文檔mongoose docs on populate得到了答案

所以代碼是這樣的：

            user.findOne({ name: 'ABC' }).
            populate({
                path: 'Cloth',
                populate: { path: 'brand' }
              })
                .then(result => {                  
                   res.json(result)
                })