使 UIButton 更改 MutableProperty 的正確方法是什么？

Question

以下代碼有效：

import UIKit
import ReactiveSwift
import ReactiveCocoa

class ViewController: UIViewController {
    let myAction = Action<UIButton, (), Never> { _ in
        return SignalProducer { observer, _ in
                observer.send(value: ())
                observer.sendCompleted()
            }
    }
    
    let aProp = MutableProperty<String>("MutablePropertyStart")
    
    override func viewDidLoad() {
        super.viewDidLoad()
        
        myAction.events.observeValues { [unowned self]_ in
            self.aProp.value = "MutablePropertyChanged"
        }
     
        view.backgroundColor = .black
    
        let button = UIButton()
        button.frame = CGRect(x:100, y:100, width:100, height:100)
        button.setTitle("Press Me", for: .normal)
        view.addSubview(button)
        button.reactive.pressed = CocoaAction(self.myAction) { sender in
            return sender
        }
        
        let label = UILabel()
        label.frame = CGRect(x:100, y:200, width:200, height: 100)
        label.text = "LabelStart"
        label.textColor = .white
        view.addSubview(label)
        
        label.reactive.text <~ aProp
    }
}

但是有沒有更正確的方法和更少的代碼？ 即，我可以讓按鈕操作直接更改屬性，而不需要 myAction 中的其他 SignalProducer 嗎？

Answer 1

如果您只是想觀察按鈕按下，我認為對 ReactiveCocoa 使用<~運算符和 controlEvents 可能會使這更整潔

self.aProp <~ button.reactive.controlEvents(.primaryActionTriggered)
    .map { _ in 
        "MutablePropertyChanged"
    }