Laravel 工廠為多列關系

Question

為我正在處理的項目創建工廠，我在創建 belongsTo 關系時遇到了問題。

在我的Cards表中，我有 2 列引用相同的關系： Card->order->id和Card->order->ref （不要問我為什么，我什至不知道）。

因此，在我的CardFactory中，我需要能夠為$card->order_ref和$card->order_id使用相同的Order實例。 使用工廠狀態，我確實創建了以下 state：

public function sold(int $userId) : Factory
{
    $createdOrder = Order::factory()->forUser($userId)->create();

    return $this->state(function (array $attributes) use ($createdOrder) {
        return [
            'state' => Card::STATE_SOLD,
            'sold' => Carbon::now()->subDay(),
            'addedincart' => Carbon::now()->subDay()->subHour(),
            'selling_date' => Carbon::now()->subDay(),
            'order_id' => $createdOrder->id,
            'order_ref' => $createdOrder->ref,
        ];
    });
}

我的OrderFactory.php ：

class OrderFactory extends Factory {
public function definition() : array
{
    return [
        'ref' => $this->faker->randomNumber(9) ,
        'state' => 5,
        'clientname' => $this->faker->name(),
        'email' => $this->faker->email(),
        'phone' => $this->faker->phoneNumber(),
        'address' => null,
        'shippingaddress' => NULL,
        'total' => $this->faker->randomFloat(2, 50, 700),
        'method' => 'creditcard',
        'user_id' => null,
        'tracking' => NULL,
        'response' => json_encode(["someFields" => "someValues"]),
        'paid_on' => now(),
        'sent_on' => now(),
        'review_sent' => '1',
        'deliverymethod' => 'email',
        'deliverycosts' => '0.00',
        'coupon_id' => NULL,
        'discount' => '0.00',
        'explanation' => NULL,
        'refund_amount' => NULL,
        'refunded_at' => NULL,
        'shipping_status' => NULL,
        'original_cards' => '[1, 2]',
        'cancel_reason' => NULL,
        'private_comment' => NULL,
        'loyalty' => '30',
        'ip' => '00.00.00.00',
        'cb' => 'someCb',
        'geoip' => NULL,
        'ecards_sent' => '1',
        'blocked_by' => NULL,
        'partner' => NULL,
        'original_giftcards' => '',
        'giftcards_sent' => '0',
        'api_data' => NULL,
        'original_products' => NULL,
        'delivered_at' => now(),
        'invoice_send_at' => NULL,
        'type' => 'cards',
        'redeem_id' => '0',
    ];
}

public function forUser(int $id) : Factory
{
    return $this->state(function (array $attributes) use ($id) {
        return [
            'user_id' => $id,
        ];
    });
}

}

在我的CardSeeder.php中：

public function run()
{
    $user = User::query()->where("email", "myAddress@gmail.com")->first();
    
    Card::factory()->sold($user->id)->count(15)->create();
    Card::factory()->selling()->count(15)->create();
}

問題是，對於每個sold的 state 創建，都使用相同的$createdOrder->id 。

對於每一行，我怎么能使用不同的順序？

Answer 1

作為文檔https://laravel.com/docs/9.x/database-testing#defining-relationships-within-factories

描述：

如果關系的列依賴於定義它的工廠，您可以將閉包分配給屬性。 閉包將接收工廠的評估屬性數組。

所以如果你想生成關系的新實例，你必須在閉包內創建它：

public function sold(int $userId) : Factory 
{ 

return $this->state(function (array $attributes) use ($userId) {
    $order=null;
    return [
        'state' => Card::STATE_SOLD,
        'sold' => Carbon::now()->subDay(),
        'addedincart' => Carbon::now()->subDay()->subHour(),
        'selling_date' => Carbon::now()->subDay(),
        'order_id' => function()use(&$order,$userId){
           $order = Order::factory()->forUser($userId)->create();
           return $order->id;
        },
        'order_ref' => function()use(&$order){
              return $order->ref;
        },
    ];
});

}