[英]Pointers to a struct inside a struct
我有兩個結構(one_d 和 two_d)。 我有一個 function 將 struct two_d *smg 作為輸入。 在 main() 中,我正在嘗試創建這樣的 smg,因此它將返回值 c 增加。
我的問題是,在創建 struct two_d smg[2] 的數組時,我不確定如何放入有關其值的內部信息,因為它是指向不同結構的指針。
那么如何在結構中使用指向結構的指針呢? 我想創建 struct two_d smg[2] 但我現在不知道如何處理其中的 struct one_d *a 字段
#include <stdio.h>
enum sid
{
DRB,
DRA,
};
struct one_d
{
unsigned int r;
unsigned int *p;
};
struct two_d
{
struct one_d *a;
enum sid z;
};
unsigned int getSmg(struct two_d *smg)
{
unsigned int c = 0;
const struct two_d *sd = NULL;
const struct one_d *ed = NULL;
for (sd = smg; sd->a != NULL; ++sd)
{
for (ed = sd->a; ed->p != NULL; ++ed)
{
if (DRA == sd->z)
{
/*P Increment the clear-state buffer size */
c += 1 + ed->r;
}
}
}
return c;
}
int main(void)
{
unsigned int rVal = 0;
struct two_d smg[2]={
//
// [0].a ={1,0},
// [0].z =DRA,
// [1].a={1,0},
// [1].z =DRA,
};
rVal = getSmg(smg);
printf("Return value is a %d\n", rVal);
printf("Return value is a l");
return( 0 );
}
好吧,至少這個編譯...我不是運行它的游戲,雖然...
物有所值...
enum sid { DRB, DRA, DRAwhoCares };
typedef struct {
unsigned int r;
unsigned int *p;
} oneD_t;
typedef struct {
oneD_t *a;
enum sid z;
} twoD_t;
unsigned int getSmg( twoD_t *smg ) {
unsigned int c = 0;
for( twoD_t *sd = smg; sd->a != NULL; +sd++ ) {
for( oneD_t *ed = sd->a; ed->p != NULL; ed++ ) {
if( DRA == sd->z ) {
/*P Increment the clear-state buffer size */
c += 1 + ed->r;
}
}
}
return c;
}
int main( void ) {
oneD_t foo[] = { { 1, NULL }, /* ... */ };
oneD_t bar[] = { { 1, NULL }, /* ... */ };
twoD_t smg[]={
{ foo, DRA, },
{ bar, DRA, },
{ NULL, DRAwhoCares, },
};
unsigned int rVal = getSmg( smg );
printf( "Return value: %u\n", rVal );
return 0; // return is not a function call... No parenthesis...
}
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