[英]use character string in R inside SQL WHERE IN statement having issues with LIKE statement
我有一個類似於下面的查詢,我需要使用一串字符,它工作正常,但當我使用 LIKE 語句時不行。 請在下面進一步閱讀
ids
[1] "0000000000000000010000001" "0000000000000000010000002" "0000000000000000010000003"
[4] "0000000000000000010000004" "0000000000000000010000005" "0000000000000000010000006"
[7] "0000000000000000010000007" "0000000000000000010000008" "0000000000000000010000009"
[10] "0000000000000000010000010"
expr1 <- sprintf("select
FSAS.a_id,
FSAS.grade,
FSAS.score,
FSAS.placement,
FSAS.start,
FSAS.completion
FROM db.Fact AS FSAS
WHERE FSAS.a_id IN (%s)", paste0(sQuote(ids, q = FALSE), collapse=", "))
sqlQuery(con, expr1)
所以上面的代碼有效,但當我添加 LIKE 語句時,下面的代碼不起作用。 我想找到所有以 FR 開頭的展示位置,因此為什么要使用 LIKE 'FR%' 但我認為它會干擾 IN 語句。 我得到的錯誤是“參數太少”。 請問我該如何糾正這個問題?
ids
[1] "0000000000000000010000001" "0000000000000000010000002" "0000000000000000010000003"
[4] "0000000000000000010000004" "0000000000000000010000005" "0000000000000000010000006"
[7] "0000000000000000010000007" "0000000000000000010000008" "0000000000000000010000009"
[10] "0000000000000000010000010"
expr1 <- sprintf("select
FSAS.a_id,
FSAS.grade,
FSAS.score,
FSAS.placement,
FSAS.start,
FSAS.completion
FROM db.Fact AS FSAS
WHERE FSAS.a_id IN (%s) and FSAS.placement LIKE 'FR%'", paste0(sQuote(ids, q = FALSE), collapse=", "))
sqlQuery(con, expr1)
要獲得 sprintf 格式字符串中的文字 % ,請將其加倍。 toString 在這里也很有用。
s <- "select
FSAS.a_id,
FSAS.grade,
FSAS.score,
FSAS.placement,
FSAS.start,
FSAS.completion
FROM db.Fact AS FSAS
WHERE FSAS.a_id IN (%s) and FSAS.placement LIKE 'FR%%'"
sprintf(s, toString(sQuote(ids, FALSE)))
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