[英]Simple Java App to calculate the average of an indefinite amount of entered numbers
[英]Java program reading indefinite amount of numbers from a user till a positive is entered
我需要編寫一個 java 程序讀取不確定數量的數字並將它們保存到數字集合中,直到用戶輸入一個(偶數)。 我嘗試了一個while循環,當在其中找到一個正數時它會停止。 但它並沒有真正起作用。 這是我嘗試過的代碼:
公共 static 無效主(字符串 [] 參數){
int programInteger = 1;
int inputtedInteger;
while (programInteger < 2) {
System.out.println("Enter a number: "); //Asks user to input a number
Scanner in = new Scanner(System.in);
inputtedInteger = Scanner(in.nextLine);
if (inputtedInteger != 0) {
System.out.println("The number "+ inputtedInteger +" that you inputted is not an even number, try again: ");
inputtedInteger=in.nextInt();
}
else if (inputtedInteger % 2 == 0){
programInteger =+1;
System.out.println("The number "+inputtedInteger+" that you entered is an even number!");
}
}
}
/* if(inputtedInteger % 2 == 0) {
System.out.println("The number "+ inmatatTal +" you entered is an even number!");
}
else {
System.out.println("Enter a number?! ");
inputtedInteger = in.nextInt();
}
修復循環邏輯中的一些事情應該可以工作:
int inputtedInteger = 0;
Scanner in = new Scanner(System.in);
while (inputtedInteger < 1) {
System.out.println("Enter a number: "); //Asks user to input a number
inputtedInteger = in.nextInt();
if (inputtedInteger % 2 != 0) {
System.out.println("The number "+ inputtedInteger +" that you inputted is not an even number, try again: ");
}
else if (inputtedInteger % 2 == 0){
System.out.println("The number "+inputtedInteger+" that you entered is an even number!");
}
}
我會為這樣的代碼設置一個大綱:
setup Scanner, create collection
while true:
userInput = scanner.nextInt()
if userInput > 0: break
collection.add(userInput)
print('user entered', collection.length(), 'numbers.')
希望有幫助。 我將讓您使用實際的 Java 語法來填寫此內容。 我在 OP 上寫了一篇評論,說明為什么您的結構無法解決手頭的問題。
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