如何在 python 中使用 Tkinter 創建后退按鈕

Question

我正在嘗試創建一個對我已實現的按鈕做出反應的 GUI。

預期 output：按下“返回”按鈕將恢復第一個 window。 [主窗口]

目前 output：按“返回”按鈕將回調 function [刪除輔助窗口的按鈕並調用原始窗口] 但不會恢復原始 Z05B8C74CBD96FBF2DE4C1A352702FFF4Z

這是我的實現：

import tkinter
from tkinter import *
from PIL import ImageTk, Image

applied_logo_path = r'C:\Users\e174701\OneDrive - Applied Materials\Desktop\amatlogo.png'
logo_path = r'C:\Users\e174701\OneDrive - Applied Materials\Desktop\amatmain.png'

font1 = ('Helvetica 15', 20)
# -----------------------------------------------------------------------------------------------------


def main_window():

    def Second_window():
        def back():
            button_previous.destroy()
            button_execute.destroy()
            main_window()
        # Second window: [User pressed "next"]

        main_window.title('MC installer')
        main_window.geometry("800x600")

        # Presenting Applied Materials logo:
        main_window_logo = ImageTk.PhotoImage(Image.open(logo_path))
        main_window_logo_label = Label(image=main_window_logo, width=800, height=300)
        main_window_logo_label.place(x=5, y=100)
        button_next.destroy()
        button_readME.destroy()
        # execute button: [will start the process]
        pixel = tkinter.PhotoImage(width=1, height=1)
        button_execute = Button(main_window, text="Execute", image=pixel, width=80, height=30, compound="c")
        button_execute.place(x=700, y=550)

        # previous button: [will return the user to the main window]
        button_previous = Button(main_window, text="Previous", image=pixel, width=80, height=30, compound="c",
                                 command=lambda: back())
        button_previous.place(x=10, y=550)
        main_window.mainloop()

    # main window general definitions:
    main_window = Tk()

    main_window.title('MC installer')
    # instead this comment need to define the upper toolbar logo.
    main_window.geometry("800x600")

    # Presenting Applied Materials logo:
    main_window_logo = ImageTk.PhotoImage(Image.open(logo_path))
    main_window_logo_label = Label(image=main_window_logo, width=800, height=300)
    main_window_logo_label.place(x=5, y=100)

    # next button: [will take the user to the next window]
    pixel = tkinter.PhotoImage(width=1, height=1)
    button_next = Button(main_window, text="Next", image=pixel, width=80, height=30, compound="c", command=lambda: Second_window())
    button_next.place(x=700, y=550)

    # exit button: [will close the installer.]
    button_exit = Button(main_window, text="Exit", image=pixel, width=80, height=30, compound="c", command=lambda: main_window.quit())
    button_exit.place(x=10, y=550)

    # read me button: [will guide the user]
    button_readME = Button(main_window, text="Read me", image=pixel, width=80, height=30, compound="c")
    button_readME.place(x=345, y=550)
    main_window.mainloop()

Answer 1

從我在 def back() function 中可以看到，您沒有破壞 window，而是調用了按鈕。

在 def Second_window() function 中，您將 GUI 命名為與主窗口相同的名稱，這將在嘗試調用其中任何一個時導致錯誤，因為代碼將不知道要恢復哪個 window。 將第二個 window 更改為 Second_window 將有助於解決此問題

def back():
            Second_window.destroy()
            main_window()

使用框架或為每個按鈕創建一個新的 window 可能會有所幫助並使導航更容易。