Object型<class 'tuple'>在 django 中加密文件時無法傳遞給 C 代碼</class>

Question

所以我想用我輸入的關鍵字加密 file.txt。 但我收到錯誤消息

Object 類型 <class 'tuple'> 不能傳遞給 C 代碼

我的問題是這段代碼：

aes = AES.new(key.encode('utf8'), AES.MODE_CTR, counter=ctr)

如果我將編碼添加到 ctr，那么我收到錯誤消息'dict' object has no attribute 'encode'

如果我刪除不向鍵和 ctr 添加任何編碼，那么我收到錯誤消息Object 類型 <class 'str'> 無法傳遞給 C 代碼

有人可以幫我解決嗎？ 我正在使用 django 使用方法 CTR 使用 AES 128 進行加密。 或者也許有人可以用另一種方法給我示例 aes 加密，但可以在 django 中運行。 這是我的完整 function 代碼：

# AES supports multiple key sizes: 16 (AES128), 24 (AES192), or 32 (AES256).
key_bytes = 16
# Takes as input a 32-byte key and an arbitrary-length plaintext and returns a
# pair (iv, ciphtertext). "iv" stands for initialization vector.
def encrypt(key, testpass):
    assert len(key) == key_bytes
    print(testpass)
    print(key)
    # Choose a random, 16-byte IV.
    iv = Random.new().read(AES.block_size)

    # Convert the IV to a Python integer.
    iv_int = int(binascii.hexlify(iv), 16)

    # Create a new Counter object with IV = iv_int.
    ctr = Counter.new(AES.block_size * 8, initial_value=iv_int)
    print(ctr)

    # Create AES-CTR cipher.
    aes = AES.new(key.encode('utf8'), AES.MODE_CTR, counter=ctr)

    # Encrypt and return IV and ciphertext.
    ciphertext = aes.encrypt(testpass)
    print(iv)
    print(ciphertext)
    return (iv, ciphertext)

這就是我所說的function：

testpass = Audio_store.objects.all().values_list('password').last()
enkripsi = encrypt("testingtesting11", testpass)

當我打印 testpass 時，它包含('testpass_3kEMV2T.txt',)

但是當我打印 testpass.encode("utf-8") 時，它什么也沒顯示

Answer 1

您的測試數據是('testpass_3kEMV2T.txt',) ，您需要從tuple中提取元素並將其作為bytes傳遞給您的encrypt方法，因為AES.encrypt方法需要bytes | bytearray | memoryview bytes | bytearray | memoryview bytes | bytearray | memoryview作為它的論據。 這是您的encrypt的一個版本，它確定您傳遞的參數是否為str並將其編碼為 bytes （但它不檢查是否為bytes ，如果您想要更嚴格的檢查，我將其作為練習留給您）。

import binascii


from Crypto.Cipher import AES
from Crypto.Util import Counter
from Crypto import Random

key_bytes = 16

# here's a rudimentary change that accepts bytes or
# str
def encrypt(key, plaintext):
    if isinstance(plaintext, str):
        plaintext = plaintext.encode("utf-8")

    assert len(key) == key_bytes
    # Choose a random, 16-byte IV.
    iv = Random.new().read(AES.block_size)

    # Convert the IV to a Python integer.
    iv_int = int(binascii.hexlify(iv), 16)

    # Create a new Counter object with IV = iv_int.
    ctr = Counter.new(AES.block_size * 8, initial_value=iv_int)
    print(ctr)

    # Create AES-CTR cipher.
    aes = AES.new(key.encode('utf8'), AES.MODE_CTR, counter=ctr)

    # Encrypt and return IV and ciphertext.
    ciphertext = aes.encrypt(plaintext)
    return (iv, ciphertext)

# for now, since you're getting your data from the db which is a 1-tuple, you have to pull out the first elem
testpass = ('testpass_3kEMV2T.txt',)
print(encrypt("a"*16, testpass[0]))

Output：

{'counter_len': 16, 'prefix': b'', 'suffix': b'', 'initial_value': 302861312392273214314458272471454024973, 'little_endian': False}
(b'\xe3\xd8\xf7\x90\xcd\x96m\xcb\xa5g)\xd1\xda\xc3\x85\r', b'-F)\x83\x9a\xf9\xe1\xc3\xfb\xfa_<^\x1c:q\x07\xa1@\xbb')