使用 Eloquent 獲取報告的用戶

Question

在我的 laravel 應用程序中，我想獲取其他用戶報告的用戶，並且對於每個用戶，我想檢索附加到他們的其他用戶的這些報告，但我不知道如何。

報告 model：

public function reporter()
    {
        return $this->belongsTo('App\Models\User', 'reporter_id');
    }

    public function reported()
    {
        return $this->belongsTo('App\Models\User', 'reported_id');
    }

用戶 model：

public function reports()
    {
        return $this->hasMany('App\Models\Report','reporter_id');
    }


    public function reported()
    {
        return $this->hasMany('App\Models\Report','reported_id');
    }

我如何創建報告：

public function create($request)
    {
        $validatedData = $request->validate(ReportValidator::$create);
        
        $report = new Report();
        $report->reportcategory_id = $request['reportcategory_id'];
        $report->reporter_id = $request['reporter_id'];
        $report->reported_id = $request['reported_id'];
        $report->body = $request['body'];
        $report->save();
        
        $report = $report->fresh([ 'category' ]);
        
        return $report;
    }

報告遷移：

Schema::create('reports', function (Blueprint $table) {
            $table->increments('id');
            $table->unsignedInteger('reporter_id')->index();
            $table->foreign('reporter_id')->references('id')->on('users')->onDelete('cascade')->onUpdate('cascade');
            $table->unsignedInteger('reported_id')->index();
            $table->foreign('reported_id')->references('id')->on('users')->onDelete('cascade')->onUpdate('cascade');
            $table->unsignedInteger('reportcategory_id')->index();
            $table->foreign('reportcategory_id')->references('id')->on('reportcategories')->onDelete('cascade')->onUpdate('cascade');
            $table->text('body')->nullable();
            $table->timestamps();
        });

Answer 1

您需要獲取用戶並加載這樣的關系

$user = User::has('reported')->with('reported')->get();