![](/img/trans.png)
[英]Having a problem with a Javascript assignment and I have no idea what the solution is, i have tried everything
[英]Having a problem with a Javascript assignment: Array and object iteration but I have no idea what the solution is, I have tried everything
在本練習中,您將使用 for....of 循環遍歷數組和對象自身的屬性。
第 1 步:給您一系列乳制品:
var dairy = ['cheese', 'sour cream', 'milk', 'yogurt', 'ice cream', 'milkshake']
創建一個名為 logDairy 的logDairy
。 在其中,控制台使用 for...of 循環記錄乳品數組中的每個項目。
預期的 output 應該是:
cheese
sour cream
milk
yogurt
ice cream
milkshake
const animal = { canJump: true }; const bird = Object.create(animal); bird.canFly = true; bird.hasFeathers = true;
創建一個名為birdCan
的 function ,在其中使用 for...of 循環遍歷鳥對象的屬性和控制台日志。 請記住,您需要控制台記錄每個鳥對象屬性的鍵和值。
我的答案:
// Task 1 var dairy = ['cheese', 'sour cream', 'milk', 'yogurt', 'ice cream', 'milkshake']; function logDairy(items) { for (const element of items) { console.log(element); } } console.log(logDairy(dairy)); // Task 2 const animal = { canJump: true }; const bird = Object.create(animal); bird.canFly = true; bird.hasFeathers = true; function birdCan(items){ for (let [key, value] of Object.entries(items)) { console.log(key, value); } } console.log(birdCan(animal)); // Task 3 function animalCan(items) { for (let [key, value] in Object.entries(items)) { console.log(key, value); } } console.log(animalCan(animal));
FAILED: Console logged expected values for logDairy - returned TypeError: items is not iterable but expected cheesesour creammilkyogurtice creammilkshake FAILED: Console logged expected values for birdCan - returned TypeError: Cannot convert undefined or null to object but expected canFly: truehasFeathers: true FAILED: Console logged expected values for animalCan - returned TypeError: Cannot convert undefined or null to object but expected canFly: truehasFeathers: truecanJump: true
var dairy = [
"cheese",
"sour cream",
"milk",
"yogurt",
"ice cream",
"milkshake",
];
function logDairy(array) {
for (const item of array) {
console.log(item);
}
}
logDairy(dairy);
const animal = {
canJump: true,
};
const bird = Object.create(animal);
bird.canFly = true;
bird.hasFeathers = true;
function birdCan(myObject) {
for (let [key, value] of Object.entries(myObject)) {
console.log(key, value);
}
}
birdCan(bird);
function animalCan(myObject) {
const props = Object.keys(Object.getPrototypeOf(myObject)).concat(
Object.keys(myObject)
);
for (const prop of props) {
console.log(prop);
}
}
animalCan(bird);
// 任務1
var milk = ['奶酪', '酸奶油', '牛奶', '酸奶', '冰淇淋', '奶昔'];
function logDairy() {
for (prop of Object.keys(dairy)){
console.log(dairy[prop]);
}
}
日志乳制品();
// 任務 2
常量動物 = {
可以跳:真
};
常量鳥 = Object.create(動物);
鳥.canFly = true;
鳥.hasFeathers = true;
function 鳥罐(){
for (prop of Object.keys(bird)) {
console.log(`${prop}: ${bird[prop]}`);
}
} 鳥可以();
// 任務 3
function animalCan() {
for (prop in bird) {
console.log(`${prop}: ${bird[prop]}`);
}
} 動物可以();
您可以使用以下代碼。 我已經提交了作業並獲得了 100/100。 希望這對你有用。 快樂的編碼...
// Task 1 var dairy = ['cheese', 'sour cream', 'milk', 'yogurt', 'ice cream', 'milkshake']; function logDairy() { for (const element of dairy) { console.log(element); } } console.log(logDairy(dairy)); // Task 2 const animal = { canJump: true }; const bird = Object.create(animal); bird.canFly = true; bird.hasFeathers = true; function birdCan() { for (keys of Object.keys(bird)) console.log(keys,": ", bird[keys]); } birdCan(); // Task 3 function animalCan() { for (prop in bird) { console.log(prop,": ", bird[prop]); } } animalCan();
希望這可以幫助。 Coursera 評分器會查看細粒度級別,即使冒號的間距也可能構成錯誤答案,並導致您的作業失敗,即使控制台沒有記錄任何錯誤。
// Task 1
var dairy = ['cheese', 'sour cream', 'milk', 'yogurt', 'ice cream', 'milkshake'];
function logDairy() {
for (const element of dairy) {
console.log(element);
}
}
console.log(logDairy(dairy));
// Task 2
const animal = {
canJump: true
};
const bird = Object.create(animal);
bird.canFly = true;
bird.hasFeathers = true;
function birdCan() {
for (keys of Object.keys(bird))
console.log(keys,": ", bird[keys]);
}
birdCan();
// Task 3
function animalCan() {
for (prop in bird) {
console.log(prop,": ", bird[prop]);
}
}
animalCan();
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.