SQL：Select 只有一行具有相同的值和過濾器

Question

我需要做一些數據庫排序和過濾：我的數據庫看起來像這樣：

ID	不	地位
32	98765	0
32	0	2
70	43210	0
70	0	2

最終的 output 需要是：

ID	不	地位
32	98765	0
70	43210	0

如果找到具有相同值的ID（如果找到奇異值，則不顯示），select 只會選擇並顯示status = 0 和no.= 0 的ID。

提前致謝！

Answer 1

試試這個，你得到准確的 output

Select ID,No,Status From YOURTABLE Where ID IN (Select ID From YOURTABLE 
Group By ID Having Count(ID) > 1)
And Status = 0 And No <> 0 

Answer 2

嘗試這個

Select ID,No,Status From TableData Where ID IN (Select ID From TableData  
Group By ID Having Count(ID) > 1)
And Status = 0 And No <> 0 

Answer 3

嘗試以下操作：

Select A.ID, A.No, A.Status From
tblname A
Join
(
  Select ID, COUNT(*) cn
  From tblname
  Group By ID
  Having COUNT(*)>1
) B
On A.ID = B.ID
Where A.Status = 0 And A.No <> 0

或者使用Exists和相關子查詢：

Select A.ID, A.No, A.Status From
tblname A
Where A.Status = 0 And A.No <> 0
And Exists (Select 1 From tblname B Where B.ID = A.ID And A.No <> B.No)

查看db<>fiddle的演示。