如何在 python 的段落句子中設置字數限制？

Question

當 append 在一個列表中時需要設置一個限制。

sent = 'Python is dynamically-typed and garbage-collected. It supports multiple programming paradigms, including structured (particularly procedural), object-oriented and functional programming.'

我只需要在一個句子中設置 5 個單詞和 append 到一個列表

output 應該 -

sent_list = ['Python is dynamically-typed and garbage-collected.', 'It supports multiple programming paradigms,', 'including structured (particularly procedural), object-oriented', 'and functional programming.']

Answer 1

嘗試這個：

words = sent.split(' ')
sent_list = [' '.join(words[n:n+5]) for n in range(0, len(words), 5)]

Answer 2

可能有點不正統：

sent_list = [re.sub(r'\s$','',x.group('pattern')) for x in 
     re.finditer('(?P<pattern>([^\s]+\s){5}|.+$)',sent)]

['Python is dynamically-typed and garbage-collected.',
 'It supports multiple programming paradigms,',
 'including structured (particularly procedural), object-oriented',
 'and functional programming.']

解釋'(?P<pattern>([^\s]+\s){5}|.+$)' ：

• (?P<pattern>... ) : 修飾，創建一個命名的捕獲組。
• ([^\s]+\s){5} ：查找非空白字符序列（一個或多個），后跟一個空格； 然后重復5次。
• |.+$ ：一旦第一個選項用盡，只需將最后一位完成。

我們使用re.finditer循環所有match objects並使用x.group('pattern')獲取匹配。 除了最后一場比賽之外，所有比賽最后都會有一個額外的空格； 擺脫它的一種方法是使用re.sub 。

Answer 3

sent = 'Python is dynamically-typed and garbage-collected. It supports multiple programming paradigms, including structured (particularly procedural), object-oriented and functional programming.'
sent_list = ['Python is dynamically-typed and garbage-collected.', 
            'It supports multiple programming paradigms,', 
            'including structured (particularly procedural), object-oriented', 
            'and functional programming.']

new_list = []
inner_string = ""
sentence_list = sent.split(" ")
for idx, item in enumerate(sentence_list):
    if (idx+1)==1 or (idx+1)%5 != 0:
        if (idx+1) == len(sentence_list):
            inner_string += item
            new_list.append(inner_string)
        else:
            inner_string += item + " "
    elif (idx+1)!=1 and (idx+1) % 5 == 0 :
        inner_string += item
        new_list.append(inner_string)
        inner_string = ""
        
print(new_list)
print(new_list == sent_list)

Output：

['Python is dynamically-typed and garbage-collected.', 'It supports multiple programming paradigms,', 'including structured (particularly procedural), object-oriented', 'and functional programming.']
True