[英]Getting the Gtk.TreePath of the first row in a Gtk.TreeView
我想在按下按鈕時選擇Gtk.TreeView
的第一行。 我知道這可以使用row_activated
,但是row_activated
需要一個Gtk.TreePath
和一個Gtk.TreeViewColumn
(我假設可以設置為None
)。 問題是我不知道如何獲取第一行的Gtk.TreePath
。
class Main(Gtk.Window):
def __init__(self):
super().__init__()
liststore = Gtk.ListStore(str)
liststore.append(['first_entry'])
liststore.append(['second_entry'])
liststore.append(['third_entry'])
treeview = Gtk.TreeView()
treeview.set_model(liststore)
renderer = Gtk.CellRendererText()
column = Gtk.TreeViewColumn('Item', renderer, text=0)
treeview.append_column(column)
button = Gtk.Button(label='button')
box = Gtk.Box()
box.set_orientation(Gtk.Orientation.VERTICAL)
box.add(button)
box.add(treeview)
self.add(box)
if __name__ == '__main__':
main = Main()
main.show_all()
Gtk.main()
在這種情況下,當按下按鈕時,我希望first_entry
(即第一行)
I found treeview.set_cursor(0)
in question: Python + GTK: How to set a selected row on gtk.treeview - Stack Overflow and I think it can be better solution.
順便說一句:你必須使用self.
通過按鈕執行treeview
中的 treeview 訪問。
import gi
gi.require_version("Gtk", "3.0")
from gi.repository import Gtk
class Main(Gtk.Window):
def __init__(self):
super().__init__()
liststore = Gtk.ListStore(str)
liststore.append(['first_entry'])
liststore.append(['second_entry'])
liststore.append(['third_entry'])
self.treeview = Gtk.TreeView()
self.treeview.set_model(liststore)
renderer = Gtk.CellRendererText()
column = Gtk.TreeViewColumn('Item', renderer, text=0)
self.treeview.append_column(column)
button = Gtk.Button(label='button')
button.connect('clicked', self.select_first)
box = Gtk.Box()
box.set_orientation(Gtk.Orientation.VERTICAL)
box.add(button)
box.add(self.treeview)
self.add(box)
def select_first(self, event):
self.treeview.set_cursor(0)
if __name__ == '__main__':
main = Main()
main.show_all()
Gtk.main()
用於 C/C++ 的set_cursor()的文檔(但可能很有用)。
似乎原始set_cursor()
也需要TreePath
但在 Python 它適用於index
。 其他函數不必使用index
而不是TreePath
編輯:
我發現您可以使用index
創建TreePath
- 作為list
或string
def select_first(self, event):
path = Gtk.TreePath.new_from_indices([0]) # it needs list because trees can be nestes, ie. [0,5,3]
#path = Gtk.TreePath.new_from_string("0") # for nested trees it can be ie. "0:5:3"
selection = self.treeview.get_selection()
selection.select_path(path)
編輯:
如果你使用self.
當您創建self.column = Gtk.TreeViewColumn('Item', renderer, text=0)
時,您可以將它與row_activated()
一起使用,但這不是 select 在我的計算機上的行(但不會引發錯誤)
def select_first(self, event):
path = Gtk.TreePath.new_from_indices([0])
self.treeview.row_activated(path, self.column)
我用於測試的完整代碼:
# https://lazka.github.io/pgi-docs/Gtk-3.0/classes/TreeSelection.html#gtk-treeselection
# https://lazka.github.io/pgi-docs/Gtk-3.0/classes/TreePath.html#Gtk.TreePath.new_from_indices
import gi
gi.require_version("Gtk", "3.0")
from gi.repository import Gtk
class Main(Gtk.Window):
def __init__(self):
super().__init__()
self.connect("destroy", Gtk.main_quit)
liststore = Gtk.ListStore(str)
liststore.append(['first_entry'])
liststore.append(['second_entry'])
liststore.append(['third_entry'])
self.treeview = Gtk.TreeView()
self.treeview.set_model(liststore)
renderer = Gtk.CellRendererText()
self.column = Gtk.TreeViewColumn('Item', renderer, text=0)
self.treeview.append_column(self.column)
button1 = Gtk.Button(label='First')
button1.connect('clicked', self.select_first)
button2 = Gtk.Button(label='Second')
button2.connect('clicked', self.select_second)
button3 = Gtk.Button(label='Third')
button3.connect('clicked', self.select_third)
box = Gtk.Box()
box.set_orientation(Gtk.Orientation.VERTICAL)
box.add(button1)
box.add(button2)
box.add(button3)
box.add(self.treeview)
self.add(box)
def select_first(self, event):
self.treeview.set_cursor(0)
def select_second(self, event):
path = Gtk.TreePath.new_from_indices([1]) # it needs list because trees can be nestes, ie. [0,5,3]
path = Gtk.TreePath.new_from_string("1") # for nested trees it can be ie. "0:5:3"
selection = self.treeview.get_selection()
selection.select_path(path)
def select_third(self, event):
path = Gtk.TreePath.new_from_indices([2]) # it needs list because trees can be nestes, ie. [0,5,3]
self.treeview.row_activated(path, self.column)
if __name__ == '__main__':
main = Main()
main.show_all()
Gtk.main()
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