[英]How to write a code to get a user input for a 6 digit integer number and check if the number is palindrome?
編寫一個 python 程序,要求用戶輸入一個 6 位的 integer 並檢查輸入是否為回文。 如果用戶未能輸入 integer 或 integer 小於 6 位,則必須要求用戶重新輸入。 (注意:編寫代碼時不應使用 TRY 和 EXCEPT,並且不應允許用戶嘗試超過 3 次。)
我對此的看法是:
for n in range(3):
while True:
i = input("Please enter a six digit integer:")
if i.isnumeric():
if len(i)==6:
i_integer = int(i)
print("Your number is:",i_integer,"and the data type is:",type(i_integer))
break
else:
print("Enter value is not numeric")
使用此代碼,如果我輸入一個六位數字,那么我必須輸入 3 次,而不是 1 次。 下面是 output。
Please enter a six digit integer:123456
Your number is: 123456 and the data type is: <class 'int'>
Please enter a six digit integer:123456
Your number is: 123456 and the data type is: <class 'int'>
Please enter a six digit integer:123456
Your number is: 123456 and the data type is: <class 'int'>
有沒有更好的方法可以在不使用 TRY 和 EXCEPT 的情況下做到這一點?
您可以使用計數器和“while”循環來代替“for”循環,如下面的代碼片段。
tries = 0
while True:
i = input("Please enter a six digit integer:")
if i.isnumeric() and len(i) == 6:
i_integer = int(i)
print("Your number is:",i_integer,"and the data type is:",type(i_integer))
break
else:
tries += 1
if tries >= 3:
break
if tries >= 3:
print("Sorry - too many tries to enter a six digit integer")
quit()
# Palindrome testing would start here
print("Going to see if this is a palindrome")
對此進行測試,我的終端上顯示了以下 output。
@Una:~/Python_Programs/Palindrome$ python3 Numeric.py
Please enter a six digit integer:12345
Please enter a six digit integer:123456
Your number is: 123456 and the data type is: <class 'int'>
Going to see if this is a palindrome
我將把它留給你來構建測試,看看輸入的數字是否是回文。
試試看。
tries = 0
while True:
i = input("Please enter a six digit integer:")
if i.isnumeric() and len(i) == 6:
i_integer = int(i)
print("Your number is:",i_integer,"and the data type is:",type(i_integer))
# Palindrome testing would start here
print("Going to see if this is a palindrome")
n=int(i)
temp=n
rev=0
while(n>0):
dig=n%10
rev=rev*10+dig
n=n//10
if(temp==rev):
print("The number is a palindrome!")
else:
print("The number isn't a palindrome!")
break
else:
tries += 1
if tries >= 3:
break
if tries >= 3:
print("Sorry - too many tries to enter a six digit integer")
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