如何讓 Turtle 的繪制速度更快？

Question

如何制作 Python 庫 Turtle，運行並在 1 個屏幕刻度內繪制一個正方形？

import turtle as t
import math

def square():
  t.penup()
  t.goto(cord_x_1, cord_y_1)
  t.pendown()
  t.goto(cord_x_2, cord_y_2)
  t.goto(cord_x_3, cord_y_3)
  t.goto(cord_x_4, cord_y_4)
  t.goto(cord_x_1, cord_y_1)
  t.penup()
 
t.speed(0)
theta = 0

print("What do you want for angle Θ?")
radians_theta = math.fmod(float(theta), 360)
sqrt =  math.sqrt((50)**2+(50)**2)

while 2 > 1: 
  radians_theta = math.fmod(float(theta), 360)

  #cord setup
  cord_x_1 = sqrt * math.cos(radians_theta)
  cord_y_1 = sqrt * math.sin(radians_theta)

  cord_x_2 = sqrt * math.cos(radians_theta + math.radians(90))
  cord_y_2 = sqrt * math.sin(radians_theta + math.radians(90))

  cord_x_3 = sqrt * math.cos(radians_theta + math.radians(180))
  cord_y_3 = sqrt * math.sin(radians_theta + math.radians(180))

  cord_x_4 = sqrt * math.cos(radians_theta + math.radians(270))
  cord_y_4 = sqrt * math.sin(radians_theta + math.radians(270))

  #repeat
  t.clear()
  square()
  theta += 30
  theta = theta % 360
  print(theta)

我想要的是讓烏龜非常快地繪制旋轉的正方形。 我嘗試將速度設置為 0，但這還不夠快。 有誰知道我怎樣才能加速烏龜？

Answer 1

當然。 有時烏龜速度不夠快，所以有一種方法可以讓 go 更快。 方法是完全禁用animation 。 t.tracer(0)將禁用 animation。所以把它放在代碼頂部附近的某個地方。 現在，在您的代碼結束時，您將需要t.update()來在海龜完成后強制更新並將其顯示在屏幕上。

Answer 2

我們可能會通過預先計算繪制的固定圖像集來簡單地添加tracer()和update() ：

from turtle import Screen, Turtle, Vec2D
from math import sin, cos, radians, sqrt
from itertools import cycle

def square(cord_1, cord_2, cord_3, cord_4):
    turtle.goto(cord_1)

    turtle.pendown()
    turtle.goto(cord_2)
    turtle.goto(cord_3)
    turtle.goto(cord_4)
    turtle.goto(cord_1)
    turtle.penup()

def draw():
    theta, cord_1, cord_2, cord_3, cord_4 = next(endless_coordinates)
    turtle.clear()
    square(cord_1, cord_2, cord_3, cord_4)
    screen.update()
    print(theta)
    screen.ontimer(draw)

theta = 0
delta = 30
diagonal = sqrt(2 * 50**2)
coordinates = []

for theta in range(0, 360, delta):
    theta_radians = radians(theta)

    cord_1 = diagonal * Vec2D(cos(theta_radians), sin(theta_radians))
    cord_2 = diagonal * Vec2D(cos(theta_radians + radians(90)), sin(theta_radians + radians(90)))
    cord_3 = diagonal * Vec2D(cos(theta_radians + radians(180)), sin(theta_radians + radians(180)))
    cord_4 = diagonal * Vec2D(cos(theta_radians + radians(270)), sin(theta_radians + radians(270)))

    coordinates.append((theta, cord_1, cord_2, cord_3, cord_4))

endless_coordinates = cycle(coordinates)

screen = Screen()
screen.tracer(False)

turtle = Turtle()
turtle.hideturtle()
turtle.penup()

draw()

screen.exitonclick()

我們還可以通過旋轉海龜本身來消除海龜級別的繪圖，將所有繪圖向下推到C級別：

from turtle import Screen, Turtle

SQUARE_SIZE = 100
DELTA = 30

CURSOR_SIZE = 20

theta = 0

def draw():
    global theta

    turtle.left(DELTA)
    screen.update()

    theta = (theta + DELTA) % 360
    print(theta)

    screen.ontimer(draw)

screen = Screen()
screen.tracer(False)

turtle = Turtle()
turtle.shape('square')
turtle.fillcolor('white')
turtle.shapesize(SQUARE_SIZE / CURSOR_SIZE)
turtle.penup()

draw()

screen.exitonclick()