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是否可以使用沒有案例的防護裝置重寫此 Haskell function?

[英]Is it possible to rewrite this Haskell function using guards with no case-of?

我有這個使用“case of”的 Haskell function,但我想弄清楚是否有可能重寫這個 function 使用警衛(“”)而不是“” 可能嗎? 任何建議都會有所幫助。

lefQ :: Ord a => LOL a -> Lang a -> Lang a
lefQ (LOL i xs) [] = []
lefQ (LOL i xs) (LOL j y:ys) = case stripPrefix xs y of
                    Nothing -> leftq (LOL i xs) ys
                    Just zs -> (LOL (j-i) zs):lefQ (LOL i xs) ys

您可以使用模式保護,因此:

lefQ :: Ord a => LOL a -> Lang a -> Lang a
lefQ (LOL i xs) [] = []
lefQ (LOL i xs) (LOL j y:ys)
    | Just zs <- stripPrefix xs y = (LOL (j-i) zs): lefQ (LOL i xs) ys
    | otherwise = leftq (LOL i xs) ys

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