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[英]returning all comments by a specific user without other document fields using mongoose
[英]Exclude specific fields in all nested document in mongoose query
我有一個以trips作為字段的ride Collection, trips是一個map,其中鍵是不同的年份。 我想查詢集合,但在每次旅行中排除乘客字段
const ride = new Schema(
{
boat_operator: {
type: Schema.Types.ObjectId,
required: true,
ref: 'User'
},
trips: {
type: Map,
of: {
passengers: [{ type: Schema.Types.ObjectId, ref: 'User' }],
available_seats: { type: Number, required: true }
},
default: new Map()
}
}
)
我試過這個
const rides = await Ride.find({ status: 'waiting' }).select("-trips.*.passengers")
我試圖 select值中的所有項目然后刪除每個相應的乘客字段
它沒有效果
這就是響應的樣子
[
{
"_id": "632a1669279c86f4ab3a4bf5",
"boat_operator": "6328c434a98212a7f57c4edc",
"trips": {
"2019": {
"passengers": [],
"available_seats": 5,
"_id": "632a1669279c86f4ab3a4bfe"
},
"2020": {
"passengers": [],
"available_seats": 5,
"_id": "632a1669279c86f4ab3a4bfc"
},
"2021": {
"passengers": [],
"available_seats": 5,
"_id": "632a1669279c86f4ab3a4bfa"
},
"2022": {
"passengers": [],
"available_seats": 5,
"_id": "632a1669279c86f4ab3a4bf8"
}
}
}
]
我想在返回的文檔中排除乘客字段
這將解決它
const rides = await Ride.aggregate([
{ "$match": { "status": "waiting" } },
{ $project: { "trips": { $objectToArray: '$trips' } } },
{ $project: { 'trips.v.passengers': 0 } },
{ $project: { "trips": { $arrayToObject: '$trips' } } }
]);
nodejs javascript mongodb mongoose
這是退回的文件
{
"_id": "632a1669279c86f4ab3a4bf5",
"trips": {
"2019": {
"available_seats": 5,
"_id": "632a1669279c86f4ab3a4bfe"
},
"2020": {
"available_seats": 5,
"_id": "632a1669279c86f4ab3a4bfc"
},
"2021": {
"available_seats": 5,
"_id": "632a1669279c86f4ab3a4bfa"
},
"2022": {
"available_seats": 5,
"_id": "632a1669279c86f4ab3a4bf8"
}
}
}
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