在 function 中執行 f-string

Question

我有一個

string = 'long company name with technologies in it'

並想要替換所有以

search_string ='techno'

帶有新令牌

replace_string = 'tech'.

我寫了一個function：

def group_tokens(company_name, string_search, string_replace):   
try:
    x = company_name.split(" ") 
    print(f"x = [re.sub('^{string_search}.*', '{string_replace}', i) for i in x]")
    exec(f"x = [re.sub('^{string_search}.*', '{string_replace}', i) for i in x]")
    x = " ".join(x)
    x = " ".join(re.split("\s+", x, flags=re.UNICODE))
    return(x)
except:
        return np.nan

如果我單獨執行這些行，它就可以工作。 但是 function 本身不起作用。

group_tokens('long company name with technologies in it', 'techno', 'tech') = 'long company name with technologies in it'

我期待

group_tokens('long company name with technologies in it', 'techno', 'tech') = 'long company name with tech in it'

如何在 function 中“執行”f-string？

Answer 1

你把這個復雜化了。 只需重新分配 x：

def group_tokens(company_name, string_search, string_replace):   
  try:
    x = company_name.split(" ") 
    x = [re.sub(f'^{string_search}.*', string_replace, i) for i in x])
    x = " ".join(x)
    x = " ".join(re.split("\s+", x, flags=re.UNICODE))
    return x
  except:
    return np.nan

但是重寫 function 可能更容易，類似於以下內容：

def group_tokens(company_name, string_search, string_replace):   
  return re.sub(f'^{string_search}\S*\s*', f'{string_replace} ', company_name);

Answer 2

def replace(string,x,y):
    words = string.split(' ')
    string = ''
    while words:
        word = words.pop(0)
        if word.startswith(x):
            word = y
        string+=word+' '
    return string[:-1]

print(replace('long company name with technologies in it', 'techno', 'tech'))

    

Answer 3

我肯定把它復雜化了。 謝謝：-）

def group_tokens(company_name, string_search, string_replace):   
  try:
    x = company_name.split(" ") 
    x = [re.sub(f'^{string_search}.*', string_replace, i) for i in x])
    x = " ".join(x)
    x = " ".join(re.split("\s+", x, flags=re.UNICODE))
    return x
  except:
   return np.nan