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[英]Dual infeasible due to empty column 'x1' in Python w/Cplex/Docplex
[英]DOcplex: the dual of the dual is not the same as primal?
我有一個非常簡單的原始問題,定義如下:
mdl = Model(name='tubs_primal')
aqua = mdl.continuous_var(name='aqua')
hydro = mdl.continuous_var(name='hydro')
typhoon = mdl.continuous_var(name='typhoon')
pump = mdl.add_constraint(aqua + hydro + typhoon <= 200, 'pump')
hour = mdl.add_constraint(9*aqua + 6*hydro + 8*typhoon<= 1566, 'hour')
tubing = mdl.add_constraint(12*aqua+16*hydro + 13*typhoon <= 2880, 'tubing')
profit = 350*aqua + 300*hydro + 320*typhoon
mdl.maximize(profit)
我也這樣寫下它的對偶問題
mdl = Model(name='tubs_dual')
pump = mdl.continuous_var(name='pump', lb=None)
hour = mdl.continuous_var(name='hour', lb=None)
tubing = mdl.continuous_var(name='tubing', lb=None)
aqua = mdl.add_constraint(pump + 9*hour + 12*tubing >= 350, 'aqua')
hydro = mdl.add_constraint(pump + 6*hour + 16*tubing >= 300, 'hydro')
typhoon = mdl.add_constraint(pump + 8*hour + 13*tubing >= 320, 'typhoon')
cost = 200*pump + 1566*hour + 2880*tubing
mdl.minimize(cost)
原始代碼完美無缺。 但是,當我運行對偶問題時,CPLEX 告訴我對偶目標和原始目標是不同的。 那么對偶的對偶問題與原始問題不同嗎? 我很納悶。 有什么幫助嗎? 謝謝。
Iteration log . . .
Iteration: 1 Dual objective = 60900.000000
objective: 66100.000
pump=200.000
hour=16.667
原因是因為沒有完整的日志顯示。 假設您使用原始方法求解 2 個模型 primal 和 dual
from docplex.mp.model import Model
mdl = Model(name='tubs_primal')
aqua = mdl.continuous_var(name='aqua')
hydro = mdl.continuous_var(name='hydro')
typhoon = mdl.continuous_var(name='typhoon')
pump = mdl.add_constraint(aqua + hydro + typhoon <= 200, 'pump')
hour = mdl.add_constraint(9*aqua + 6*hydro + 8*typhoon<= 1566, 'hour')
tubing = mdl.add_constraint(12*aqua+16*hydro + 13*typhoon <= 2880, 'tubing')
profit = 350*aqua + 300*hydro + 320*typhoon
mdl.maximize(profit)
mdl.parameters.lpmethod=1
mdl.solve(log_output=True)
print("obj=",mdl.objective_value)
mdl2 = Model(name='tubs_dual')
pump = mdl2.continuous_var(name='pump', lb=None)
hour = mdl2.continuous_var(name='hour', lb=None)
tubing = mdl2.continuous_var(name='tubing', lb=None)
aqua = mdl2.add_constraint(pump + 9*hour + 12*tubing >= 350, 'aqua')
hydro = mdl2.add_constraint(pump + 6*hour + 16*tubing >= 300, 'hydro')
typhoon = mdl2.add_constraint(pump + 8*hour + 13*tubing >= 320, 'typhoon')
cost = 200*pump + 1566*hour + 2880*tubing
mdl2.minimize(cost)
mdl2.parameters.lpmethod=1
mdl2.solve(log_output=True)
print("obj=",mdl2.objective_value)
然后你會得到
Iteration log . . .
Iteration: 1 Objective = 60900.000000
obj= 66100.0
Iteration log . . .
Iteration: 1 Scaled infeas = 0.000000
Switched to devex.
Iteration: 2 Objective = 66100.000000
obj= 66100.0
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