[英]How to create a cumulative count distinct with partition by in SQL?
我有一個包含用戶數據的表,想創建一個不同的累積計數,但這種類型的 window function 不存在。 這是我的桌子
date | user-id | purchase-id
2020-01-01 | 1 | 244
2020-01-03 | 1 | 244
2020-02-01 | 1 | 524
2020-03-01 | 2 | 443
現在,我想要一個像這樣的購買 ID 的不同計數:
date | user-id | purchase-id | cum_purchase
2020-01-01 | 1 | 244 | 1
2020-01-03 | 1 | 244 | 1
2020-02-01 | 1 | 524 | 2
2020-03-01 | 2 | 443 | 1
我試過了
Select
dt,
user_id,
count(distinct purchase_id) over (partition by user_id ORDER BY date ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) as cum_ct
from table
我得到一個錯誤,我不能將 count distinct 與 order by 語句一起使用。 該怎么辦?
像這樣的東西
Select
dt as [date],
user_id,
purchase_id
SUM(CASE WHEN rn = 1 THEN 1 ELSE 0 END) over (partition by user_id ORDER BY dt ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) as cum_ct
from (
SELECT
dt,
user_id,
purchase_id,
ROW_NUMBER() OVER (PARTITION BY user_id, purchase_id ORDER BY dt) as RN
FROM sometable
) sub
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