SQL - regexp_extract JSON 字符串

Question

我正在嘗試從以下字符串中提取 locationID

{"type":"player","topic_id":"555","topic_name":"sfd","userId":116,"userLocation":{"countryCode":"BR","locationId":21,"locationCity":"Rio de Janeiro"}}

例如，我可以使用以下 safe_cast( topic_id safe_cast(regexp_extract(h.events.label,r'"topic_id":"([a-zA-Z0-9-_. ]+)"') as int64提取 topic_id但這對locationId不起作用。我猜這是因為嵌套的字典？但不確定如何解決這個問題。

Answer 1

您最好使用json function 而不是正則表達式function。

WITH sample_data AS (
  SELECT '{"type":"player","topic_id":"555","topic_name":"sfd","userId":116,"userLocation":{"countryCode":"BR","locationId":21,"locationCity":"Rio de Janeiro"}}' json 
)
SELECT CAST(JSON_VALUE(json, '$.userLocation.locationId') AS INT64) AS locationId 
  FROM sample_data;

+------------+
| locationId |
+------------+
|         21 |
+------------+

這不適用於locationId 。 我猜這是因為嵌套的字典？

• 我猜這是因為topic_id的值是一個字符串"555" ，而locationId的值是一個 integer 21 。
• r'"locationId":([a-zA-Z0-9-_. ]+)'將適用於locationId但更簡單的正則表達式將是r'"locationId":(\d+)'