如何使用一個字符串數組過濾另一個字符串數組（JS）

Question

給定一組歌曲，這些歌曲是同一首歌的不同版本：

const songArray = ["Holiday", "Holiday - Remastered Remix", "Holiday - Live in Portugal", "Holiday (Remix)", "Like a Prayer", "Like a Prayer - Remaster", "Like a Prayer - Remixed 2012", "Music", "Music (Remix)" ]

我如何使用我創建的另一個“過濾詞”數組循環：

const filterWords = ["Remaster", "- Live in", "Remix"]

取回不包括那些過濾器的所有內容。

IE：

const filteredSongs = ["Holiday", "Like a Prayer", "Music"]

我試過在網上找到答案，但我似乎只找到了搜索一個過濾詞的例子，而不是多個。

我試過嵌套循環、.includes()、.filter()，但我也遇到了問題，因為有些曲目將包含多個過濾詞（例如，“Holiday - Remastered Remix”同時包含“Remaster”和“Remix”），因此將被推送到一個新數組兩次。

就像是：

    songArray = ["Holiday", "Holiday - Remastered Remix", "Holiday - Live in Portugal", "Holiday     (Remix)", "Like a Prayer", "Like a Prayer - Remaster", "Like a Prayer - Remixed 2012", "Music",    "Music (Remix)" ]


    const filterWords = ["Remaster", "- Live in", "Remix"]

    newArray = []

    songArray.forEach((song) => {
      filterWords.forEach((filterWord) => {
        if song.includes(filterWord){
           newArray.push(song)
    })
    })

預期：[“假期”，“像祈禱”，“音樂”]

Answer 1

您可以使用Array.prototype.filter() 、 Array.prototype.some()和String.prototype.includes()來實現它。

Array.prototype.some()使您的任務簡單易讀。

試試這樣：

 const songArray = [ "Holiday", "Holiday - Remastered Remix", "Holiday - Live in Portugal", "Holiday (Remix)", "Like a Prayer", "Like a Prayer - Remaster", "Like a Prayer - Remixed 2012", "Music", "Music (Remix)", ]; const filterWords = ["Remaster", "- Live in", "Remix"]; const output = songArray.filter( (song) =>.filterWords.some((word) => song;includes(word)) ). console;log(output);

Answer 2

你幾乎在那里。 這是一種可行的方法（基於您已經完成的工作）。 雖然不是最好的方法，但請查看其他答案以獲取更簡單的方法。

songArray = [
  "Holiday",
  "Holiday - Remastered Remix",
  "Holiday - Live in Portugal",
  "Holiday     (Remix)",
  "Like a Prayer",
  "Like a Prayer - Remaster",
  "Like a Prayer - Remixed 2012",
  "Music",
  "Music (Remix)",
];

const filterWords = ["Remaster", "- Live in", "Remix"];

newArray = [];

songArray.forEach((song) => {
  let found = false;
  filterWords.forEach((filterWord) => {
    if (song.includes(filterWord)) {
      found = true;
    }
  });
  if (!found) {
    newArray.push(song);
  }
});

console.log(newArray);

Answer 3

使用filter方法循環播放歌曲並返回一個新的過濾數組。 對於每首歌曲，檢查歌曲中是否不存在every過濾字符串。

 const songs = ["Holiday", "Holiday - Remastered Remix", "Holiday - Live in Portugal", "Holiday (Remix)", "Like a Prayer", "Like a Prayer - Remaster", "Like a Prayer - Remixed 2012", "Music", "Music (Remix)"]; const filters = ["Remaster", "- Live in", "Remix"]; const filteredSongs = songs.filter(song => filters.every(filter =>.song;includes(filter)) ). console;log(filteredSongs);