我的 While 循環無法按代碼中的預期運行

Question

print ("Welcome To Femboii's Restaraunt")
Name = input ("What's Your Name Sir?\n").capitalize()
EvilGuys = ["Jack", "Ben", "Maria"]
if Name in EvilGuys:
    Evil_Status = input ("Are You Evil " + Name + "?\n").capitalize()
    if Evil_Status == "Yes":
        Good_Deeds = input ("How Many Good Deeds Have You Done Today " + Name + "?\n")
        Bad_Deeds = input ("How Many Bad Deeds Have You Done Today " + Name + "?\n")
        Good_Deeds = int(Good_Deeds)
        Bad_Deeds = int(Bad_Deeds)
    elif Evil_Status == "No":
        print ("Oh, So You Aren't Evil, Come In You're Welcome!")
    else:
        print ("Sorry I Didn't Understand You, So Ill Just Take It As A No")
    if Good_Deeds >= Bad_Deeds:
        print ("Oh, So You Aren't Evil, Come In You're Welcome!")
    if Good_Deeds < Bad_Deeds:
        print ("GET OUTTTT RIGHT NOWWWWWWWWWW!!!!!!!!!!")
        exit ()
print ("Welcome " + Name)
FoodMenu = ("Pizza, Crepe, Burger And Shawrma.")
DrinksMenu = ("Black Coffee, Latte, Mocha, Espresso, Crapuccino And Sparkling Water")
FoodMenuList = ["Pizza", "Crepe", "Burger", "Shawrma"]
DrinksMenuList = ["Black Coffee", "Latte", "Mocha", "Espresso", "Crapuccino", "Sparkling Water"]
Order = input ("Here's Our Food Menu\n" + FoodMenu + "\nAnd Here's Our Drinks Menu\n" + DrinksMenu + "\nChoose What Serves You The Best.\n").capitalize
while Order not in FoodMenuList or Order not in DrinksMenuList:
    if Order in FoodMenuList or Order in DrinksMenuList:
        break
    if Order not in FoodMenuList or Order not in DrinksMenuList:
        input ("Sorry, I Didn't Understand What You Said, Can You Repeat?\n").capitalize()
print (Order)

我試着做到這一點，如果他要的東西不在菜單中，我會告訴他代碼是 ai 隨便什么

無法理解他，如果他繼續這樣做，它會繼續說

Sorry, I Didn't Understand What You Said, Can You Repeat

並且 while 循環不會停止

Answer 1

嗯，你忘了將input(...)推入Order 。 目前是：

while Order not in FoodMenuList or Order not in DrinksMenuList:
    if Order in FoodMenuList or Order in DrinksMenuList:
        break
    if Order not in FoodMenuList or Order not in DrinksMenuList:
        input ("Sorry, I Didn't Understand What You Said, Can You Repeat?\n").capitalize()
print (Order)

你需要：

while Order not in FoodMenuList or Order not in DrinksMenuList:
    if Order in FoodMenuList or Order in DrinksMenuList:
        break
    if Order not in FoodMenuList or Order not in DrinksMenuList:
        Order = input ("Sorry, I Didn't Understand What You Said, Can You Repeat?\n").capitalize() # here
print (Order)

你也可以重寫你的程序，這樣就不會有重復的代碼，但這是你的選擇，呵呵。

就個人而言，我會寫這樣的東西，因為它正在檢查在while條件下是否在菜單中：

while Order not in FoodMenuList or Order not in DrinksMenuList:
    Order = input ("Sorry, I Didn't Understand What You Said, Can You Repeat?\n").capitalize()
print (Order)

Answer 2

while not (Order in FoodMenuList or Order in DrinksMenuList:
    if Order in FoodMenuList or Order in DrinksMenuList:
        break
    if not (Order in FoodMenuList or Order in DrinksMenuList):
        input ("Sorry, I Didn't Understand What You Said, Can You Repeat?\n").capitalize()
print (Order)

大概跟邏輯有關。 你看：

not P and not Q != not (P and Q) 

Answer 3

正如其他人已經指出的那樣，問題似乎出在程序的邏輯上。

while Order not in FoodMenuList or Order not in DrinksMenuList:

在這里，您要檢查訂單是否不在食物菜單中，或者訂單是否不在飲料菜單中。

這將始終為True ，因為訂單不能同時出現在食物菜單和飲料菜單中。

您要做的是將or替換為and 。 這樣，只有當訂單不在兩個菜單中時，它才會返回True 。

另一種方法是組合兩個菜單並檢查項目是否在其中：

while Order not in FoodMenuList+DrinksMenuList:

也與問題無關，但不建議使用+符號來格式化字符串：

"How Many Bad Deeds Have You Done Today " + Name + "?\n"

一個更好的方法是使用格式字符串：

f"How Many Bad Deeds Have You Done Today {Name}?\n"

Answer 4

在這個問題的答案中，我的回答似乎有點不受歡迎。 行中存在語法錯誤

Order = input ("Here's Our Food Menu\n" + FoodMenu + "\nAnd Here's Our Drinks Menu\n" + DrinksMenu + "\nChoose What Serves You The Best.\n").capitalize

capitalize() 是一個屬性，而不是字符串數據類型的特征，因此需要用括號調用它。

當 function 在沒有括號的情況下被調用時，一個完全不同的元素存儲在變量“Order”中，這就是代碼與 FoodMenuList 和 DrinkMenuList 中提供的關鍵字無關的原因