[英]Extract data from nested JSON inside Mysql cell
我需要從 MySQL 單元格 $row["detail"] 中的 JSON 中提取一些數據。 這是我需要的數據:options->408->value":"72" 和 options->409->value":"80"
這是我的 JSON
"132":{
"id":132,
"name":"Taille",
"invoice_name":"Taille",
"displayed_in_preview":"1",
"displayed_in_order":"1",
"input_suffix":"cm",
"use_qty":"0",
"required":"1",
"ignored_if_empty":"1",
"options":{
"408":{
"id":408,
"id_option":104,
"name":"Hauteur ",
"selected_by_default":"0",
"check_default":"0",
"position":0,
"min":70,
"max":74,
"default":"72",
"weight":0,
"delivery_impact":0,
"value":"72",
},
"409":{
"id":409,
"id_option":105,
"name":"Largeur",
"selected_by_default":"0",
"check_default":"0",
"position":1,
"min":70,
"max":100,
"default":"70",
"weight":0,
"delivery_impact":0,
"value":"80",
}
}
但我收到一個錯誤。
我試試這段代碼:
$url = $row["detail"];
$JSON_arr = json_decode($url, true);
foreach($json_arr as $key){
print $key -> options -> value
但我收到一個錯誤。
這是您的代碼示例:
<?php
$json = '{
"132": {
"id": 132,
"name": "Taille",
"invoice_name": "Taille",
"displayed_in_preview": "1",
"displayed_in_order": "1",
"input_suffix": "cm",
"use_qty": "0",
"required": "1",
"ignored_if_empty": "1",
"options": {
"408": {
"id": 408,
"id_option": 104,
"name": "Hauteur ",
"selected_by_default": "0",
"check_default": "0",
"position": 0,
"min": 70,
"max": 74,
"default": "72",
"weight": 0,
"delivery_impact": 0,
"value": "72"
},
"409": {
"id": 409,
"id_option": 105,
"name": "Largeur",
"selected_by_default": "0",
"check_default": "0",
"position": 1,
"min": 70,
"max": 100,
"default": "70",
"weight": 0,
"delivery_impact": 0,
"value": "80"
}
}
}
}';
$JSON_arr = json_decode($json, true);
foreach ($JSON_arr as $row) {
foreach ($row['options'] as $option => $data)
echo 'option ' . $option . ' -> ' .'value: ' . $data['value'] . PHP_EOL;
}
Output:
option 408 -> value: 72
option 409 -> value: 80
或者在這里
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