字符串轉換為json，如何獲取label和數據？

Question

props.record.DataUpdate.draft 的值

{"FirstName": "This is my firstname","MiddleName": "This is my middlename","LastName": "this is my lastname"}

讓 newData = JSON.parse(props.record.DataUpdate.draft)

控制台日志（新數據）

{
  "FirstName": "This is my firstname",
  "MiddleName": "This is my middlename",
  "LastName": "this is my lastname"
}

這是我的數據庫

  id: {
    type: Sequelize.INTEGER,
    primaryKey: true,
    autoIncrement: true,
  },
  tableNameToBeUpdated: {
    type: Sequelize.STRING,
  },
  tableIdToBeUpdated: {
    type: Sequelize.STRING,
  },
  draft: {
    type: Sequelize.JSON,
  },
  CreatedDate: {
    type: Sequelize.DATE,
  },
  LastUpdateDate: {
    type: Sequelize.DATE,
  },
  status: {
    type: Sequelize.STRING,
  },

我在這里想要的是獲得具有透視值的 label (Fistname,Lastname,Middlename)，

請注意label 可以根據保存在草稿列中的字符串進行更改

如何做到這一點？

Answer 1

像這樣的東西：

const jsonString = {"FirstName": "This is my firstname","MiddleName": "This is my middlename","LastName": "this is my lastname"}


for (var key in jsonString) {
       console.log(key + " -> " + jsonString[key]);
}

這給了我 Output：

'FirstName -> This is my firstname'
'MiddleName -> This is my middlename'
'LastName -> this is my lastname'

編輯：好的，我以你的帖子為例（沒有單引號）。 然后只需執行您發布的內容，然后使用 for 循環：

const jsonString = '{"FirstName": "This is my firstname","MiddleName": "This is my middlename","LastName": "this is my lastname"}'

const jsonObject = JSON.parse(jsonString)

for (var key in jsonObject) {
  console.log(key + " -> " + jsonObject[key]);
}