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使用 Python 更新 MySQL 中的選擇行

[英]Update select row in MySQL with Python

我正在編寫一個代碼,它首先查詢 MySQL 表,找到一個沒有分配給用戶的電話號碼,並用用戶指定的新用戶更新它。 這是我的代碼:

import mysql.connector

mydb = mysql.connector.connect(
  host="127.0.0.1",
  user="root",
  password="password",
  database="DID_MASTER"
)

mycursor = mydb.cursor()
mycursor.execute("SELECT DID FROM JAX2 WHERE ASSIGNEE = ''")
myresult = mycursor.fetchall()

location = input("Enter users location: :")
name = input('Enter users name: ')

for x in myresult:
    print('Free number to be used: ', x)

    sql = "UPDATE JAX2 SET ASSIGNEE = %s WHERE DID = %s"
    val = (name, x)

    mycursor.executemany(sql, val)  
    mydb.commit()

    break

查詢工作正常,但問題在於更新部分。 它返回以下錯誤:

Enter users name: Joe Smith
Free number to be used:  (1235136500,)
Traceback (most recent call last):
  File "/Users/user1/Desktop/old mac Desktop/DID Project/DB_Testing.py", line 27, in <module>
    mycursor.executemany(sql, val)  
  File "/Users/user1/Library/Python/3.9/lib/python/site-packages/mysql/connector/cursor_cext.py", line 406, in executemany
    self.execute(operation, params)
  File "/Users/user1/Library/Python/3.9/lib/python/site-packages/mysql/connector/cursor_cext.py", line 266, in execute
    prepared = self._cnx.prepare_for_mysql(params)
  File "/Users/user1/Library/Python/3.9/lib/python/site-packages/mysql/connector/connection_cext.py", line 738, in prepare_for_mysql
    raise ProgrammingError(
mysql.connector.errors.ProgrammingError: Could not process parameters: str(Joe Smith), it must be of type list, tuple or dict

更新錯誤:

raceback (most recent call last):
  File "/Users/nbecirovic/Desktop/old mac Desktop/DID Project/DB_Testing.py", line 27, in <module>
    mycursor.executemany(sql, val)  
  File "/Users/nbecirovic/Library/Python/3.9/lib/python/site-packages/mysql/connector/cursor_cext.py", line 406, in executemany
    self.execute(operation, params)
  File "/Users/nbecirovic/Library/Python/3.9/lib/python/site-packages/mysql/connector/cursor_cext.py", line 266, in execute
    prepared = self._cnx.prepare_for_mysql(params)
  File "/Users/nbecirovic/Library/Python/3.9/lib/python/site-packages/mysql/connector/connection_cext.py", line 726, in prepare_for_mysql
    result = self._cmysql.convert_to_mysql(*params)
_mysql_connector.MySQLInterfaceError: Python type tuple cannot be converted

似乎您將 x 直接傳遞給更新查詢,但 x 是一個元組,因此您必須獲取第一個元素,然后將其添加到 SQL 更新查詢。

正如@lucas-fernandes回答的那樣,你必須使用帶有executemany的列表

sql = "UPDATE JAX2 SET ASSIGNEE = %s WHERE DID = %s"
did = x[0]
val = [(name, did)]

mycursor.executemany(sql, val)  
mydb.commit()

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