[英]Can I extend an existing class (e.g. String) with a custom trait in Scala?
考慮簡單的特征TypeName
trait TypeName {
def typeName(): String
}
對於自定義類,我很清楚如何為typeName
方法指定我的實現。
class Point(val x: Int, val y: Int) extends TypeName {
def typeName(): String = {
"Point"
}
}
這現在允許我編寫這樣的函數
def printlnTypeName[T <: TypeName](value: T) = {
println(value.typeName());
}
但是,如果我想為標准庫類提供此功能。 這樣我就可以將String
、 Vector
或Array
傳遞給此printlnTypeName
函數並打印它們的類型名稱!
我該怎么做?
OOP 方法是為標准庫類引入包裝器並使它們擴展特性
trait TypeName {
def typeName(): String
}
class Point(val x: Int, val y: Int) extends TypeName {
override def typeName(): String = "Point"
}
class StringHolder(value: String) extends TypeName {
override def typeName(): String = "String"
}
class VectorHolder[A](value: Vector[A]) extends TypeName {
override def typeName(): String = "Vector"
}
// class VectorHolder[A <: TypeName](value: Vector[A]) extends TypeName {
// override def typeName(): String = s"Vector[${value.head.typeName()}]"
// }
class ArrayHolder[A](value: Array[A]) extends TypeName {
override def typeName(): String = "Array"
}
def printlnTypeName[T <: TypeName](value: T) =
println(value.typeName())
FP 方式是引入一個類型類(這是一種更靈活的方式)
// type class
trait TypeName[A] {
def typeName(): String
}
object TypeName {
// instances
implicit val stringTypeName: TypeName[String] = () => "String"
implicit def vectorTypeName[A](implicit
aTypeName: TypeName[A]
): TypeName[Vector[A]] = () => s"Vector[${aTypeName.typeName()}]"
implicit def arrayTypeName[A](implicit
aTypeName: TypeName[A]
): TypeName[Array[A]] = () => s"Array[${aTypeName.typeName()}]"
}
class Point(val x: Int, val y: Int)
object Point {
implicit val pointTypeName: TypeName[Point] = () => "Point"
}
def printlnTypeName[T](value: T)(implicit tTypeName: TypeName[T]) =
println(tTypeName.typeName())
https://kubuszok.com/2018/implicits-type-classes-and-extension-methods-part-1/
https://tpolecat.github.io/2013/10/12/typeclass.html https://tpolecat.github.io/2015/04/29/f-bounds.html
https://books.underscore.io/shapeless-guide/shapeless-guide.html#sec:generic:type-classes (第 3.1 章)
https://www.baeldung.com/scala/type-classes
https://docs.scala-lang.org/scala3/book/types-type-classes.html
您可以使用現有的類型類:
// libraryDependencies += scalaOrganization.value % "scala-reflect" % scalaVersion.value
import scala.reflect.runtime.universe.{TypeTag, typeOf}
def printlnTypeName[T: TypeTag](value: T) =
println(typeOf[T])
要么
// libraryDependencies += "com.chuusai" %% "shapeless" % "2.3.10"
import shapeless.Typeable
def printlnTypeName[T: Typeable](value: T) =
println(Typeable[T].describe)
( def foo[T: TC](value: T)
是def foo[T](value: T)(implicit tc: TC[T])
的語法糖)
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