PHP：以天、周、月、年為單位的組時間戳
[英]PHP: Group timestamps in days, weeks, months, years
問題描述
在我的應用程序中，我使用的是 RRD，但在幾個特定的場景中，我想獲取和分組數據（根據時間戳按天、周、月、年）。
這是一個更好地理解我的例子：
我們有兩個數據源（全部，活動）的數組。 在每個數據源中，鍵是時間戳，時間戳之間的間隔是 86400 秒。
$arr = [
"all" => [
"1664236800" => 0,
"1664323200" => 0,
"1664409600" => 0,
"1664496000" => 0,
"1664582400" => 0,
"1664668800" => 0,
"1664755200" => 0,
"1664841600" => 0,
"1664928000" => 0,
"1665014400" => 0,
"1665100800" => 0,
"1665187200" => 0,
"1665273600" => 0,
"1665360000" => 0,
"1665446400" => 0,
"1665532800" => 0,
"1665619200" => 0,
"1665705600" => 0,
"1665792000" => 0,
"1665878400" => 0,
"1665964800" => 0,
"1666051200" => 0,
"1666137600" => 0,
"1666224000" => 0,
"1666310400" => 0,
"1666396800" => 0,
"1666483200" => 0,
"1666569600" => 0,
"1666656000" => 0,
"1666742400" => 0,
"1666828800" => 0,
"1666915200" => 0,
"1667001600" => 0,
"1667088000" => 0,
"1667174400" => 0,
"1667260800" => 0,
"1667347200" => 0,
"1667433600" => 0,
"1667520000" => 0,
"1667606400" => 0,
"1667692800" => 0,
"1667779200" => 0,
"1667865600" => 0,
"1667952000" => 0,
"1668038400" => 0,
"1668124800" => 0,
"1668211200" => 0,
"1668297600" => 0,
"1668384000" => 0,
"1668470400" => 0,
"1668556800" => 0,
"1668643200" => 0,
"1668729600" => 0,
"1668816000" => 0,
"1668902400" => 0,
"1668988800" => 0,
"1669075200" => 0,
"1669161600" => 0,
"1669248000" => 0,
"1669334400" => 0,
"1669420800" => 0,
"1669507200" => 0,
"1669593600" => 0,
"1669680000" => 0,
"1669766400" => 0,
"1669852800" => 0,
"1669939200" => 0,
"1670025600" => 0,
"1670112000" => 0,
"1670198400" => 0,
"1670284800" => 0,
"1670371200" => 0,
"1670457600" => 0,
"1670544000" => 0,
"1670630400" => 0,
"1670716800" => 0,
"1670803200" => 0,
"1670889600" => 0,
"1670976000" => 0,
"1671062400" => 0,
"1671148800" => 0,
"1671235200" => 0,
"1671321600" => 0,
"1671408000" => 0,
"1671494400" => 0,
"1671580800" => 0,
"1671667200" => 0,
"1671753600" => 0,
"1671840000" => 0,
"1671926400" => 0,
"1672012800" => 0,
"1672099200" => 0,
"1672185600" => 0,
"1672272000" => 0,
],
"active" => [
"1664236800" => 0,
"1664323200" => 0,
"1664409600" => 0,
"1664496000" => 0,
"1664582400" => 0,
"1664668800" => 0,
"1664755200" => 0,
"1664841600" => 0,
"1664928000" => 0,
"1665014400" => 0,
"1665100800" => 0,
"1665187200" => 0,
"1665273600" => 0,
"1665360000" => 0,
"1665446400" => 0,
"1665532800" => 0,
"1665619200" => 0,
"1665705600" => 0,
"1665792000" => 0,
"1665878400" => 0,
"1665964800" => 0,
"1666051200" => 0,
"1666137600" => 0,
"1666224000" => 0,
"1666310400" => 0,
"1666396800" => 0,
"1666483200" => 0,
"1666569600" => 0,
"1666656000" => 0,
"1666742400" => 0,
"1666828800" => 0,
"1666915200" => 0,
"1667001600" => 0,
"1667088000" => 0,
"1667174400" => 0,
"1667260800" => 0,
"1667347200" => 0,
"1667433600" => 0,
"1667520000" => 0,
"1667606400" => 0,
"1667692800" => 0,
"1667779200" => 0,
"1667865600" => 0,
"1667952000" => 0,
"1668038400" => 0,
"1668124800" => 0,
"1668211200" => 0,
"1668297600" => 0,
"1668384000" => 0,
"1668470400" => 0,
"1668556800" => 0,
"1668643200" => 0,
"1668729600" => 0,
"1668816000" => 0,
"1668902400" => 0,
"1668988800" => 0,
"1669075200" => 0,
"1669161600" => 0,
"1669248000" => 0,
"1669334400" => 0,
"1669420800" => 0,
"1669507200" => 0,
"1669593600" => 0,
"1669680000" => 0,
"1669766400" => 0,
"1669852800" => 0,
"1669939200" => 0,
"1670025600" => 0,
"1670112000" => 0,
"1670198400" => 0,
"1670284800" => 0,
"1670371200" => 0,
"1670457600" => 0,
"1670544000" => 0,
"1670630400" => 0,
"1670716800" => 0,
"1670803200" => 0,
"1670889600" => 0,
"1670976000" => 0,
"1671062400" => 0,
"1671148800" => 0,
"1671235200" => 0,
"1671321600" => 0,
"1671408000" => 0,
"1671494400" => 0,
"1671580800" => 0,
"1671667200" => 0,
"1671753600" => 0,
"1671840000" => 0,
"1671926400" => 0,
"1672012800" => 0,
"1672099200" => 0,
"1672185600" => 0,
"1672272000" => 0,
]
];
我想按月對這些數據進行分組。
示例響應：
$arr = [
"1664236800" => [ // 27 September ( this is first value from fetch array)
"all" => [
"1664236800" => 0,
"1664323200" => 0,
"1664409600" => 0,
"1664496000" => 0,
],
"active" => [
"1664236800" => 0,
"1664323200" => 0,
"1664409600" => 0,
"1664496000" => 0,
],
],
"1664582400" => [ // 1st October
"all" => [
"1664582400" => 0,
"1664668800" => 0,
"1664755200" => 0,
"1664841600" => 0,
"1664928000" => 0,
"1665014400" => 0,
"1665100800" => 0,
"1665187200" => 0,
"1665273600" => 0,
"1665360000" => 0,
"1665446400" => 0,
"1665532800" => 0,
"1665619200" => 0,
"1665705600" => 0,
"1665792000" => 0,
"1665878400" => 0,
"1665964800" => 0,
"1666051200" => 0,
"1666137600" => 0,
"1666224000" => 0,
"1666310400" => 0,
"1666396800" => 0,
"1666483200" => 0,
"1666569600" => 0,
"1666656000" => 0,
"1666742400" => 0,
"1666828800" => 0,
"1666915200" => 0,
"1667001600" => 0,
"1667088000" => 0,
"1667174400" => 0,
],
"active" => [
"1664582400" => 0,
"1664668800" => 0,
"1664755200" => 0,
"1664841600" => 0,
"1664928000" => 0,
"1665014400" => 0,
"1665100800" => 0,
"1665187200" => 0,
"1665273600" => 0,
"1665360000" => 0,
"1665446400" => 0,
"1665532800" => 0,
"1665619200" => 0,
"1665705600" => 0,
"1665792000" => 0,
"1665878400" => 0,
"1665964800" => 0,
"1666051200" => 0,
"1666137600" => 0,
"1666224000" => 0,
"1666310400" => 0,
"1666396800" => 0,
"1666483200" => 0,
"1666569600" => 0,
"1666656000" => 0,
"1666742400" => 0,
"1666828800" => 0,
"1666915200" => 0,
"1667001600" => 0,
"1667088000" => 0,
"1667174400" => 0,
],
],
"1667260800" => [ // 1st November
"all" => [
"1667260800" => 0,
"1667347200" => 0,
"1667433600" => 0,
"1667520000" => 0,
"1667606400" => 0,
"1667692800" => 0,
"1667779200" => 0,
"1667865600" => 0,
"1667952000" => 0,
"1668038400" => 0,
"1668124800" => 0,
"1668211200" => 0,
"1668297600" => 0,
"1668384000" => 0,
"1668470400" => 0,
"1668556800" => 0,
"1668643200" => 0,
"1668729600" => 0,
"1668816000" => 0,
"1668902400" => 0,
"1668988800" => 0,
"1669075200" => 0,
"1669161600" => 0,
"1669248000" => 0,
"1669334400" => 0,
"1669420800" => 0,
"1669507200" => 0,
"1669593600" => 0,
"1669680000" => 0,
"1669766400" => 0,
],
"active" => [
"1667260800" => 0,
"1667347200" => 0,
"1667433600" => 0,
"1667520000" => 0,
"1667606400" => 0,
"1667692800" => 0,
"1667779200" => 0,
"1667865600" => 0,
"1667952000" => 0,
"1668038400" => 0,
"1668124800" => 0,
"1668211200" => 0,
"1668297600" => 0,
"1668384000" => 0,
"1668470400" => 0,
"1668556800" => 0,
"1668643200" => 0,
"1668729600" => 0,
"1668816000" => 0,
"1668902400" => 0,
"1668988800" => 0,
"1669075200" => 0,
"1669161600" => 0,
"1669248000" => 0,
"1669334400" => 0,
"1669420800" => 0,
"1669507200" => 0,
"1669593600" => 0,
"1669680000" => 0,
"1669766400" => 0,
],
],
"1669852800" => [ // 1st December
"all" => [
"1669852800" => 0,
"1669939200" => 0,
"1670025600" => 0,
"1670112000" => 0,
"1670198400" => 0,
"1670284800" => 0,
"1670371200" => 0,
"1670457600" => 0,
"1670544000" => 0,
"1670630400" => 0,
"1670716800" => 0,
"1670803200" => 0,
"1670889600" => 0,
"1670976000" => 0,
"1671062400" => 0,
"1671148800" => 0,
"1671235200" => 0,
"1671321600" => 0,
"1671408000" => 0,
"1671494400" => 0,
"1671580800" => 0,
"1671667200" => 0,
"1671753600" => 0,
"1671840000" => 0,
"1671926400" => 0,
"1672012800" => 0,
"1672099200" => 0,
"1672185600" => 0,
"1672272000" => 0,
],
"active" => [
"1669852800" => 0,
"1669939200" => 0,
"1670025600" => 0,
"1670112000" => 0,
"1670198400" => 0,
"1670284800" => 0,
"1670371200" => 0,
"1670457600" => 0,
"1670544000" => 0,
"1670630400" => 0,
"1670716800" => 0,
"1670803200" => 0,
"1670889600" => 0,
"1670976000" => 0,
"1671062400" => 0,
"1671148800" => 0,
"1671235200" => 0,
"1671321600" => 0,
"1671408000" => 0,
"1671494400" => 0,
"1671580800" => 0,
"1671667200" => 0,
"1671753600" => 0,
"1671840000" => 0,
"1671926400" => 0,
"1672012800" => 0,
"1672099200" => 0,
"1672185600" => 0,
"1672272000" => 0,
],
]
];
我能做到這一點的最好方法是什么？
我的方法是轉換date("Yd", $timestamp)中的每個時間戳並按響應分組。 （不知道效果如何）
2 個解決方案
解決方案1
0 2022-12-28 14:43:46
最簡單的方法是遍歷原始數組，並為每個時間戳計算正確的月度槽：
$result = array();
foreach($arr as $type => $items)
{
foreach($items as $timestamp => $value)
{
// compute first day of month
$d = new DateTime();
$d->setTimestamp(intval($timestamp)); // load timestamp into a DateTime object
$d->setTimeZone(new DateTimeZone('UTC'));
$d->setTime(0, 0, 0); // remove hours, minutes and seconds parts (if needed)
$d->modify('first day of this month');
$firstMonthTimestamp = strval($d->getTimestamp());
// create result array structure the first time
if(!array_key_exists($firstMonthTimestamp, $result)) $result[$firstMonthTimestamp] = array();
if(!array_key_exists($type, $result[$firstMonthTimestamp])) $result[$firstMonthTimestamp][$type] = array();
// append element to the month list
$result[$firstMonthTimestamp][$type][$timestamp] = $value ;
}
}
print_r($result);
解決方案2
0 2022-12-29 11:14:15
正如經常發生的那樣，在你提出一個問題之后，一個答案就會突然出現在你的腦海中。
上面的解決方案很好，但我需要能夠按小時、天、周、月和年對這些數據進行分組
經過幾天的反思，這是我的解決方案。
$groupData = (new Grouper())->group(new GroupByMonth(), $arr);
石斑魚.php
class Grouper
{
public function group(GrouperInterface $service, $data)
{
$dataSources = array_keys($data);
$timestamps = array_keys($data[$dataSources[0]]);
$groupData = [];
$lastKey = null;
foreach ($timestamps as $timestamp) {
if ($service->isNewGroup($timestamp)) {
$groupData[$timestamp] = array_fill_keys($dataSources, []);
$lastKey = $timestamp;
}
foreach ($dataSources as $ds) {
$groupData[$lastKey][$ds][$timestamp] = $data[$ds][$timestamp];
}
}
return $groupData;
}
}
GroupByMonth.php
class GroupByMonth implements GrouperInterface
{
private int $endTimestamp = -1;
public function isNewGroup(int $timestamp): bool
{
if ($this->endTimestamp >= $timestamp) {
return false;
}
$this->endTimestamp = $this->calculateEndTimestamp($timestamp);
return true;
}
private function calculateEndTimestamp(int $timestamp): int
{
list($year, $month) = explode('-', date('Y-n', $timestamp));
$daysInMonth = cal_days_in_month(CAL_GREGORIAN, $month, $year);
$date = \DateTime::createFromFormat("Y-n-d H:i:s", "{$year}-{$month}-{$daysInMonth} 23:59:59");
return $date->getTimestamp();
}
}
這對我來說是一個更好的解決方案，因為它允許我編寫更多分組功能
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