python if 語句。 和比較運算符

Question

如何制作一個使變量小於或等於 4 且大於 1 的 if 語句

我試過 <= 4 或 >1: 但它給了我一個語法錯誤，對於 <= 4 和 >=1:

我原以為如果 if 語句不小於或等於 4 且大於 1，它就不會執行

代碼

if bitches > 1:
    print("Haram")
    print("Astagfirullah")

if bitches < 1:
    print("Halal")
    print("Mashallah")

wives = int(input("How many wives do you have? "))

if wives < 1:
    print("What a faliure no wife no life")
    print("OUT OF MY HOUSE!")

if wives <= 4:
    print("Mashallah")
    print("Halal Brother")

if wives >= 5:
    print("Astagfirullah")
    print("ONLY 4 WIVES GET OUT OF MY HOME")```

basically, this is the code I was playing around with if statements, and then for the part where it says 

```if wives <= 4:
    print("Mashallah")
    print("Halal Brother")```

I wanna make it where it'll wait to verify that the value of wives is less than or equal to 4 AND greater than the value of 1

Answer 1

像這樣使用

import os

d = 3
if (d <= 4) and (d >= 1):
    print("yes")

Answer 2

好的，基本上問題是 if 語句構造正確，但不是我想要的方式，但是當我將它移動到 if 1 <= x <= 4 時：感謝 John。 G，小於或等於4，大於1，它運行並執行，這次沒有語法錯誤，

if 1 <= wives <= 4: