刪除除包含特定短語的字符串以外的所有內容

Question

我有一個包含許多 email 地址的列表。 格式類似如下：

Business Name 01    email01@business01.com; email02@business01.com; email03@business01.com; email04@business01.com; email05@business01.com;
Business Name 02    email01@business02.com; email02@business02.com; email03@business02.com; email04@business02.com; email05@business02.com;
Business Name 03    email01@business03.com; email02@business03.com; email03@business03.com; email04@business03.com; email05@business03.com;

我希望刪除除以“email02”和“email04”開頭的電子郵件之外的所有內容。 所以列表應該是這樣的：

Business Name 01    email02@business01.com; email04@business01.com;
Business Name 02    email02@business02.com; email04@business02.com;
Business Name 03    email02@business03.com; email04@business03.com;

與這個斗爭。 有任何想法嗎？

Answer 1

• Ctrl + H
• 查找內容： (?<=\h)(?!email0[24])\S+@\S+
• 替換為： LEAVE EMPTY
• TICK環繞
• SELECT正則表達式
• 全部替換

解釋：

(?<=\h)             # positive lookbehind, make sure we have space before
(?!email0[24])      # negative lookahead, make sure we aven't email02 or email04 after
\S+                 # 1 or more on space
@                   # @
\S+                 # 1 or more on space

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