簡體   English   中英

SAP HANA:無法使用 COUNT 和 CASE function IN SQL 生成所需的 output

[英]SAP HANA: Not able to generate the required output with COUNT and CASE function IN SQL

這是一個場景,單個用戶分配給多個分支(1 到許多)

我想根據分配給該用戶的辦公室對用戶進行分組。 根據分配的辦公室,我想在 select 語句中創建 2 列:

  1. 分配給該用戶的辦公室數量

  2. 分配給該用戶的辦公室名稱

這是我用 SQL 得到的 output(見下文):

USER_LABEL          NUMBER_OFFICE_ASSIGNED   BRANCH_ASSIGNED      
-------------------------------------------------------------
FARAG                       1                  HQ
FARAG                       1                  SCM
FARAG                       1                  TCD
FARAG                       1                  TCM

這是我需要的 output:

USER_LABEL          NUMBER_OFFICE_ASSIGNED   BRANCH_ASSIGNED      
-------------------------------------------------------------
FARAG                       4                  HQ,SCM,TCD,TCM

怎么做?

SQL代碼如下:

SELECT us.USER_LABEL ,
count(od.office_id) AS "NUMBER_OFFICE_ASSIGNED",
CASE 
   WHEN od.OFFICE_ID=4 THEN 'HQ' 
   WHEN od.OFFICE_ID=5 THEN 'TCM'
   WHEN od.OFFICE_ID=6 THEN 'TCD'
   WHEN od.OFFICE_ID=7 THEN 'SCM'
   WHEN od.OFFICE_ID=8 THEN 'SSAAC' 
ELSE 'No branch assigned. Check with Admin'
END AS "BRANCH_ASSIGNED"    
FROM VIEW_USER_SETUP us
INNER JOIN USERS_DEPARTMENTS ud 
on(us.USER_ID=ud.USER_ID)
INNER JOIN DEPARTMENT_SETUP ds
on(ud.DEPARTMENT_ID=ds.DEPARTMENT_ID)
INNER JOIN DEPARTMENT_OFFICE do 
on(ds.DEPARTMENT_ID=do.DEPARTMENT_ID)
INNER JOIN OFFICE_DETAILS od 
on(do.OFFICE_ID=od.OFFICE_ID)
WHERE
   ds.ACTIVE_STATUS ='Y'
AND 
   do.ACTIVE_STATUS='Y'
AND 
   od.ACTIVE_STATUS='Y'
AND 
   us.ACTIVE_STATUS ='Y'
AND 
   us.USER_TYPE ='D'
AND 
   us.USER_LABEL NOT IN('Emergency Room','General Doctor','General Doctor Oph')
GROUP BY 
    us.USER_LABEL, 
    od.OFFICE_ID
ORDER BY 
    us.USER_LABEL ASC;

首先,您應該從GROUP BY子句中刪除od.OFFICE_ID ,因為最終您不想按OFFICE_ID進行分組。 此更改要求您對CASE投影應用聚合,因為它使用OFFICE_ID 基於您所需的 output 的正確聚合方法是 function STRING_AGG

結果語句看起來像

SELECT 
   us.USER_LABEL ,
   count(od.office_id) AS "NUMBER_OFFICE_ASSIGNED",
   STRING_AGG(CASE .... END, ',') AS "BRANCH_ASSIGNED"    
FROM ...
WHERE ...
GROUP BY 
    us.USER_LABEL
ORDER BY 
    us.USER_LABEL ASC;

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM