[英]pynput on_press triggerd by own keyboard.press
如標題中所述,pynput 偵聽器的 function on_press
由其自己的按鍵觸發。
我嘗試做幾件事,比如添加一個 boolean,這樣當代碼本身運行 keypress 或 keyrelease 時,它不會打印或按下按鍵,甚至會增加大量延遲,但這些都不起作用。
代碼:
from pynput import keyboard
from pynput.keyboard import Key, Controller
import time
k = Controller()
randomVar = True
def on_press(key):
global randomVar
if randomVar:
print(key)
randomVar = False
k.press(key)
time.sleep(0.45)
randomVar = True
def on_release(key):
global randomVar
if randomVar:
print(key)
randomVar = False
k.release(key)
time.sleep(0.45)
randomVar = True
# Collect events until released
with keyboard.Listener(suppress=True, on_press=on_press, on_release=on_release) as listener:
try:
listener.join()
except Exception as e:
print('{0} was pressed'.format(e.args[0]))
當我按d
時預期為 output
'd'
'd'
實際 output:
'd'
'd'
'd'
'd'
'd'
'd'
...
編輯:我也嘗試將所有內容都放在 on_press 中,但這給出了相同的結果:
def on_press(key):
global randomVar
if randomVar:
print(key)
randomVar = False
k.press(key)
k.release(key)
time.sleep(0.45)
randomVar = True
def on_release(key):
pass
我的解決方案是一種糟糕的方法,但目前經過數小時的努力,這是我唯一能想到的。 它停止監聽器然后按下鍵,然后再次啟動監聽器,使其成為一個停止和啟動監聽器的循環,這是非常次優的
我很想聽聽人們怎么說這會有什么不同,但就目前而言,這是我唯一的解決方案:
from pynput import keyboard
from pynput.keyboard import Controller
k = Controller()
def on_press(key):
global listener
print(str(key))
listener.stop()
def on_release(key):
pass
while True:
listener = keyboard.Listener(suppress=True, on_press=on_press, on_release=on_release)
listener.start()
listener.join()
k.press("l")
k.release("l")
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