計算兩個日期之間的差異

Question

我試過這樣的

<script type="text/javascript">
     var date2=02/09/2009;
     var date1=03/12/2009;
     var diff = date1.getDate()-date2.getDate();
     alert (diff);

</script>

但它不起作用，是因為getDate僅適用於Date嗎？

如何找到這兩個日期之間的差異？ 我無法使用此功能，因為我在salesforce CRM apex頁面中添加了javascript？

編輯1：事實上這也不起作用

<script type="text/javascript">
     var date2= new Date ("02/09/2009");
     var date1= new Date ("04/09/2009");
     var diff = date1.getDate()-date2.getDate();
     alert (diff);

</script>

編輯2：它不能正常工作......

<script type="text/javascript">
     var date2= "02/09/2009";
     var date1= "04/09/2009";
     var diff2 =    new Date(Date.parse("03/12/2009")-
                        Date.parse("02/09/2009")).toLocaleDateString();

// var new_date = new Date（1970,01,01）; // var diff3 = diff2.getDate（）; alert（diff2）;

</script>

Answer 1

<script language="JavaScript">
<!--
function dstrToUTC(ds) {
 var dsarr = ds.split("/");
 var mm = parseInt(dsarr[0],10);
 var dd = parseInt(dsarr[1],10);
 var yy = parseInt(dsarr[2],10);
 return Date.UTC(yy,mm-1,dd,0,0,0);
}

function datediff(ds1,ds2) {
 var d1 = dstrToUTC(ds1);
 var d2 = dstrToUTC(ds2);
 var oneday = 86400000;
 return (d2-d1) / oneday;
}

// test cases are below

var a; var b;

a = "01/09/1999";
b = "01/10/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "01/12/1999";
b = "01/19/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "01/19/1999";
b = "01/12/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "01/03/1999";
b = "01/13/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "04/30/1999";
b = "05/01/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "05/30/1999";
b = "06/01/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "02/28/1999";
b = "03/01/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "02/28/2000";
b = "03/01/2000";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "01/01/1999";
b = "12/31/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "01/01/2000";
b = "12/31/2000";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "12/15/1999";
b = "01/15/2001";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

// -->
</script>

Answer 2

date2 = 02/09/2009不被視為日期。 它以這種方式工作。 首先它是02/09，它返回0.2222222222222222並且除以2009（0.2222222222222222/2009）。 最后你得到了一個結果date2 = 0.0001106133510314695。 以同樣的方式計算date1的結果。

這不是有效的操作。 如果要定義日期。 確保您以正確的日期格式放置數據。

使用新的Date（）或Date.parse（“02/09/2009”）

編輯：

   new Date(Date.parse("03/12/2009")-Date.parse("02/09/2009")).toLocaleDateString() Or
   new Date(date1- date2).toLocaleDateString()

不是那個工作.. ??

編輯：

可能這會工作..你可以試試這個..

 Date.parse("03/12/2009")-Date.parse("02/09/2009") / (24*60*60*1000) 

它返回31天

它似乎對我有用..但在我的時區它花了03/12/2009作為第3個月的第11天和2009年

（24 * 60 * 60 * 1000）=每天的毫秒數

Answer 3

getDate是Date對象的一種方法。 因為任何文檔都明確說明它返回0到31范圍內的月份日期。如果不是同一個月，嘗試從另一個中減去一個是沒有意義的。

Answer 4

diff.setTime(Math.abs(date1.getTime() - date2.getTime()));

timediff = diff.getTime();

weeks = Math.floor(timediff / (1000 * 60 * 60 * 24 * 7));
timediff -= weeks * (1000 * 60 * 60 * 24 * 7);

days = Math.floor(timediff / (1000 * 60 * 60 * 24)); 
timediff -= days * (1000 * 60 * 60 * 24);

hours = Math.floor(timediff / (1000 * 60 * 60)); 
timediff -= hours * (1000 * 60 * 60);

mins = Math.floor(timediff / (1000 * 60)); 
timediff -= mins * (1000 * 60);

secs = Math.floor(timediff / 1000); 
timediff -= secs * 1000;

alert(weeks + " weeks, " + days + " days, " + hours + " hours, " + mins + " minutes, and " + secs + " seconds");

Answer 5

1. getDate（）返回月中的日期，在您的情況下：9和12。

2. 您應該通過以下方式明確定義日期對象。 月份是0，因此0 = 1月，1 = 2月...

   var date2 = new Date（2009,1,9）;

3. 這些是數字，而不是字符串。 如果您想使用字符串作為日期，那么您需要完全符合該格式，沒有任何內容是可選的：

   var newDate = new Date（“month day，year hours：minutes：seconds”）; var date2 = new Date（“2009年2月9日00:00:00”）;

[編輯]完整的解決方案，如果日期格式為mm / dd / yyyy，差異應以天為單位：

<script type="text/javascript">
    function daysFromString(dateString)
    {
        // split strings at / and return array
        var splittedString = dateString.split("/");
        // make a new date. Caveat: Months are 0-based in JS
        var newDate = new Date(parseInt(splittedString[2], 10), parseInt(splittedString[0], 10)-1, parseInt(splittedString[1], 10));
        // returns days since jan 1 1970
        return Math.round(newDate.getTime() / (24*3600*1000));
    }

    var dateString2 = "02/09/2009";
    var dateString1= "03/12/2009";
    var dateDays1 = daysFromString(dateString1);
    var dateDays2 = daysFromString(dateString2);
    var diff = dateDays1 - dateDays2;
    alert (diff);
</script>

Answer 6

使用Date.parse（date1） - Date.parse（date2）

Answer 7

這里解釋了如何在javascript中找到兩個日期之間的差異

Answer 8

是。 您必須使用Date對象，如下所示

var d = new Date(2009,9,19); //19th october, months are 0-based
var d2 = new Date(2009,10,12);
var diff = (d2 - d)/60000;  //diff in minutes
alert(diff / 24);   //difference in hours

Answer 9

嘗試

var diff2 =    Date.parse("03/12/2009") - Date.parse("02/09/2009");

它會以毫秒為單位給出日期之間的差異。 將此數字除以86,400,000，差異將以天為單位。

Answer 10

<script type="text/javascript">
function GetD()
{
    var date1 = new Date ( 2009 , 09 , 02 );
    var date2 = new Date ( 2009 , 12 , 03 );        

    var diff = days_between (date1,date2);
    alert ( diff );
}
function days_between(date1, date2) {

    // The number of milliseconds in one day
    var ONE_DAY = 1000 * 60 * 60 * 24;

    // Convert both dates to milliseconds
    var date1_ms = date1.getTime();
    var date2_ms = date2.getTime();

    // Calculate the difference in milliseconds
    var difference_ms = Math.abs(date1_ms - date2_ms);

    // Convert back to days and return

    return Math.round(difference_ms/ONE_DAY);
}
</script>