使用preg_replace格式化

Question

圖案和更換時遇到麻煩。 我怎樣才能使替代品成為最終產品，例如

INSERT INTO `table` (`person`, `file`) VALUES
('test','test'),
('test2','test2'),
('test3','test3');

我正在嘗試將字符串插入SQL，但是我需要格式化下面的當前字符串才能這樣做，並且我需要將字符串test3：test3的最后一部分或任何文本內容關閉SQL模式（'test3 '，'test3'）;

<?php
$string = 'test:test test2:test2 test3:test3';
$pattern = '';
$replacement = '';
echo preg_replace($pattern, $replacement, $string);
?>

另外，它也可以有這樣的字符串嗎？ 'test@test.com:test test2:test2'而電子郵件始終在冒號之前。

Answer 1

嘗試這樣的事情：

$string = 'test:test test2:test2 test3:test3';
$patterns = array("/([^\s:]+):([^\s:]+)/", "/\s++\(/");
$replacements = array("('$1', '$2')", ", (");
$sql = 'INSERT INTO `table` (`person`, `file`) VALUES ' . preg_replace($patterns, $replacements, $string) . ';';
echo $sql . "\n";

一個解釋：

Regex 1
  ([^\s:]+)   # match one or more chars other than white space chars and colons and store it in group 1
  :           # match a colon 
  ([^\s:]+)   # match one or more chars other than white space chars and colons and store it in group 2 
Replacement 1
  (           # insert a '('
  '$1'        # insert what is matched in group 1 and surround it with single quotes
  ,           # insert ', '
  '$2'        # insert what is matched in group 2 and surround it with single quotes
  )           # insert a ')'

Regex 2
  \s++        # match one or more white space chars
  \(          # match a '('
Replacement 2
  , (         # insert ', ('