[英]C++ How to read two lines from string to separate strings?
我有兩行的字符串foo:
string foo = "abc \n def";
我如何從字符串foo讀取這2行:第一行到字符串a1,第二行到字符串a2? 我需要完成:字符串a1 =“ abc”; 字符串a2 =“ def”;
使用字符串流:
#include <string>
#include <sstream>
#include <iostream>
int main()
{
std::string foo = "abc \n def";
std::stringstream foostream(foo);
std::string line1;
std::getline(foostream,line1);
std::string line2;
std::getline(foostream,line2);
std::cout << "L1: " << line1 << "\n"
<< "L2: " << line2 << "\n";
}
檢查此鏈接以了解如何閱讀行,然后將行拆分為單詞:
C ++打印出字數限制
您可能將其讀入字符串流,然后從該流中將兩個單詞輸出為單獨的字符串。
http://www.cplusplus.com/reference/iostream/stringstream/stringstream/
這對我來說似乎是最簡單的解決方案,盡管stringstream方法也可以。
請參閱: http : //www.sgi.com/tech/stl/find.html
std::string::const_iterator nl = std::find( foo.begin(), foo.end(), '\n' ) ;
std::string line1( foo.begin(), nl ) ;
if ( nl != foo.end() ) ++nl ;
std::string line2( nl, foo.end() ) ;
然后修剪線條:
std::string trim( std::string const & str ) {
size_t start = str.find_first_of( " " ) ;
if ( start == std::string::npos ) start = 0 ;
size_t end = str.find_last_of( " " ) ;
if ( end == std::string::npos ) end = str.size() ;
return std::string( str.begin()+start, str.begin()+end ) ;
}
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